METALS ARE MAGNETIC(and maybe metalloids)
3.67 grams is the volume of the solution
Answer:
This list of electron configurations of elements contains all the elements in increasing order of atomic number.
To save room, the configurations are in noble gas shorthand. This means part of the electron configuration has been replaced with the element symbol of the noble gas symbol. Look up the electronic configuration of that noble gas and include that value before the rest of the configuration.
Explanation:
hope this help
The given question is incomplete . The complete question is :
In ionic bonding, during the transfer of electrons between two neutrally charged atoms, one electron moves from one atom to another. What are the new relative charges between the two atoms?
a. The giving atom and receiving atom are both negatively charged
b. The giving atom is now positively charged and the receiving atom is now negatively charged.
c. The giving and receiving atom are both positively charged
d. The giving atom is now negatively charged and the receiving atom is now positively charged.
Answer: The giving atom is now positively charged and the receiving atom is now negatively charged.
Explanation:
Ionic compounds are formed by transference of electrons between metals and non metals. The bond formed between a metal and a non-metal is always ionic in nature.
For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.
Thus when one electron moves from one atom to another, the metal acquires a positive charge and the non metal acquires negative charge.
For example:
is formed by transfer of one electron from sodium to chlorine , thus forming
and 
We will use the expression for freezing point depression ∆Tf
∆Tf = i Kf m
Since we know that the freezing point of water is 0 degree Celsius, temperature change ∆Tf is
∆Tf = 0C - (-3°C) = 3°C
and the van't Hoff Factor i is approximately equal to 2 since one molecule of KCl in aqueous solution will produce one K+ ion and one Cl- ion:
KCl → K+ + Cl-
Therefore, the molality m of the solution can be calculated as
3 = 2 * 1.86 * m
m = 3 / (2 * 1.86)
m = 0.80 molal