1) we can calculate the molecular weight of H₃PO₄
atomic mass (H)=1 amu
atomic mass (P)=31 amu
atomic mass (O)=16 amu
molecular weight (H₃PO₄)=3(1)+31+4(16)=98 amu.
1 mol (H₃PO₄)=98 g
1 mol= 6.022 * 10²³ molecules.
2) we calculate the mass of 4.00*10²³ molecules.
98 g-------------------6.022*10²³ molecules
x------------------------4.00*10²³ molecules
x=(98 g * 4.00*10²³ molecules) / 6.022*10²³ molecules≈65 g
Answer: 65 g
Answer:
Wavelength of light in (nm) = 579 nm
Explanation:
At first you find out the amount of energy needed to just eject one electron. This is given by 
this energy is given in question in kj/mole. This is the work function of cesium for each electron is equal to the planc'k einstein equation.
Answer:
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Answer:
the mass of one mole of an element, or Avogadro's number (6.02 x 1023) of atoms, is equal to its atomic mass in grams. In other words, 1 amu = 1 gram/mole. So if the mass of one hydrogen atom is 1 amu, the mass of one mole of hydrogen is 1 gram.
Explanation:
Answer:
16.82 L.
Explanation:
- We can use the general law of ideal gas: PV = nRT.
where, P is the pressure of the gas in atm (P = 1.0 atm, STP conditions).
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = mass/molar mass = (12.0 g)/(15.99 g/mol) = 0.7505 mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 0.0°C + 273 = 273.0 K, STP conditions).
<em>∴ V = nRT/P</em> = (0.7505 mol)(0.0821 L.atm/mol.K)(273.0 K)/(1.0 atm) = <em>16.82 L.</em>
