Here we have to write a simple equation which describes the action of the enzyme catalase.
The equation is: The concentration of the complex [ES] = ![\frac{[E]0}{1+\frac{Km}{[S]} }](https://tex.z-dn.net/?f=%5Cfrac%7B%5BE%5D0%7D%7B1%2B%5Cfrac%7BKm%7D%7B%5BS%5D%7D%20%7D)
Let us consider an enzyme catalyses reaction E + S ⇄ ES → E + P
Where E, S, ES and P are enzyme, substrate, complex and product respectively.
The concentration of the complex [ES] =
, where
is the Michaelis constant.
[E]₀ and [S] is the initial concentration of enzyme and concentration of substrate respectively.
The correct answer is option c
Answer:your answer is 0.95
Explanation:
Because you put the number down if it is in the hundreds then put into a decimal that it is in the hundredths:)
Answer: 462 g
Explanation:molar mass is M= 63.55 +2·(12.01+14.01)= 115.59 g/mol.
Mass m= n·M = 4.0 mol·115.59 g/mol= 462.36 g