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3 years ago

A compound whose water solution conducts electricity and turns phenolphthalein pink is

Chemistry

1 answer:

Ede4ka [16]3 years ago

4 0

Answer:

The compound is an <em>alkali</em>

Explanation:

Although acids and bases in solution can conduct electricity due to the presence of free ions available to carry charges, bases or alkalis turn phenolphthalein indicator pink; as opposed to acids which give colourless test on the indicator.

The anayte compound is therefore a concentrated alakli solution.

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For the Zn - Cu^2+ voltaic cell Zn(s) + Cu^2+(aq, 1M) + Cu(s) E degree _cell = 1.10 V Given that the standard reduction potentia

Fittoniya [83]

Answer : The value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

Explanation :

Here, copper will undergo reduction reaction will get reduced. Zinc will undergo oxidation reaction and will get oxidized.

The oxidation-reduction half cell reaction will be,

Oxidation half reaction: $Zn\rightarrow Zn^{2+}+2e^-$

Reduction half reaction: $Cu^{2+}+2e^-\rightarrow Cu$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode. That means, gold shows reduction and occurs at cathode and chromium shows oxidation and occurs at anode.

The overall balanced equation of the cell is,

$Zn+Cu^{2+}\rightarrow Zn^{2+}+Cu$

To calculate the $E^o_{(Cu^{2+}/Cu)}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

$E^o_{cell}=E^o_{(Cu^{2+}/Cu)}-E^o_{(Zn^{2+}/Zn)}$

Putting values in above equation, we get:

$1.10V=E^o_{(Cu^{2+}/Cu)}-(-0.76V)$

$E^o_{(Cu^{2+}/Cu)}=0.34V$

Hence, the value of $E^o_{(Cu^{2+}/Cu)}$ is, 0.34 V

8 0

3 years ago

How many Protons, electrons, and neutrons are in Dysprosium? <br><br> EASY POINTS?

Nadya [2.5K]

Answer:

Number of Protons - 66

Number of Neutrons - 97

Number of Electrons - 66

Explanation:

You're welcome :3

4 0

3 years ago

Which element had the greatest average atomic mass

Musya8 [376]

potatoes cause otatoes are delicious goodness i eating potatoes everyday

5 0

3 years ago

Read 2 more answers

Select the three most acidic hydrogen atoms in lactic acid, CH3CH(OH)CO2H, and rank them in order of decreasing acidity. Explain

Olin [163]

It is easier to determine this if we draw the structural formula of lactic acid as shown in the attached picture. There are three functional groups in lactic acid: carboxyl group, hydroxyl group, and the parent alkane chain. Any of the hydrogens in the alkane chain is the least acidic. Then, it is followed by the H in the hydroxyl group. The most acidic is the H in the carboxyl group.