Answer:
ionize
Explanation:
Acids are chemical substances that lose/donate their hydrogen ion (H+) when they react with water. This property of acids is termed IONIZATION. In a chemical reaction involving acids and bases, acids release their proton or hydrogen ion (H+) in the presence of water solutions to form a conjugate base, which is usually an anion.
For example, in the chemical reaction;
HX + H20 -------> X- + H30+
HX is the acid because it loses its electron to water and forms the anion, X-, which is the conjugate base. Hence, it can be said that acid HX ionizes in water.
Answer:
ΔS° = -268.13 J/K
Explanation:
Let's consider the following balanced equation.
3 NO₂(g) + H₂O(l) → 2 HNO₃(l) + NO(g)
We can calculate the standard entropy change of a reaction (ΔS°) using the following expression:
ΔS° = ∑np.Sp° - ∑nr.Sr°
where,
ni are the moles of reactants and products
Si are the standard molar entropies of reactants and products
ΔS° = [2 mol × S°(HNO₃(l)) + 1 mol × S°(NO(g))] - [3 mol × S°(NO₂(g)) + 1 mol × S°(H₂O(l))]
ΔS° = [2 mol × 155.6 J/K.mol + 1 mol × 210.76 J/K.mol] - [3 mol × 240.06 J/K.mol + 1 mol × 69.91 J/k.mol]
ΔS° = -268.13 J/K
This isn't chemistry at all, but the Mormons are called the Church of Jesus Christ of Latter-Day Saints.
The enthalpy change for melting ice is called the entlaphy of fusion. Its value is 6.02 kj/mol. This means for every mole of ice we melt we must apply 6.02 kj of heat. We can calculate the heat needed with the following equation:
Q = N x ΔH
where:
Q = heat
N = moles
ΔH = enthalpy
In this problem we would like to calculate the heat needed to melt 35 grams of ice at 0 °C. This problem can be broken into three steps:
1. Calculate moles of water
2. multiply by the enthalpy of fusion
3. Convert kJ to J.
Step 1 : Calculate moles of water
![[ 75g ] x (\frac{1 mol}{18.02g} ) =](https://tex.z-dn.net/?f=%5B%2075g%20%5D%20x%20%28%5Cfrac%7B1%20mol%7D%7B18.02g%7D%20%29%20%3D)
Step 2 : Multiply by enthalpy of fusion
Q = N × ΔH = <em> [ Step 1 Answer ]</em> × 6.02 =
Step 3 : Convert kJ to J
![[ Step 2 Answer ] x (\frac{1000j}{1kJ} ) =](https://tex.z-dn.net/?f=%5B%20Step%202%20Answer%20%5D%20x%20%28%5Cfrac%7B1000j%7D%7B1kJ%7D%20%29%20%3D)
Finally rounding to 2 sig figs (since 34°C has two sig figs) we get
Q Would Equal ____
Answer:
The answer is 37amu
Explanation:
We are given:
Chlorine-35: atomic mass =35 amu and percent abundance =75.5% ≡ 0.755
Chlorine-37: atomic mass = x amu and percent abundance =24.5% ≡ 0.25
From table, relative atomic mass of Chlorine is 35.5
⇒(0.755 × 35) + (24.5 × x) = 35.5
26.402 + 24.5x = 35.5
∴ x = 9.075 ÷ 24.5 = 0.37 ≡ 37.
∴ mass of Chlorine 37 = 37amu
