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3 years ago

Can someone please answer my unanswered question on my profile please I will give brainliest

Mathematics

2 answers:

Alborosie3 years ago

7 0

I will help u if u need it

Goryan [66]3 years ago

7 0

I'll try to help if it's one that i know

You might be interested in

A circular plate has a diameter of 6 inches.

Scorpion4ik [409]

D. 9pi square inches

The formula for the area of a circle is <span>π x r^2
Since the diameter is 6, the radius (r) is 3
3^2 = 9
This times pi will give you the area of the plate
</span>

5 0

3 years ago

Helene invested a total of $1,000 in two simple-interest bank accounts. One account paid 8% annual interest; the other paid 9% a

Lelu [443]

Answer: -600 and 1600 were invested into the two accounts.

Step-by-step explanation:

x = amount invested in the first account.

y = amount invested in the second account.

You start off with this equation

$x + y = 1000$

$0.08x + 0.09y=86$

Subtract both sides by y.

$x=1000-y$

Subsitude 1000 - x for x for the second equation.

$0.08(1000-y)+0.09y=$86$

Use the distributive property to solve for y.

$80-0.08y+0.09y=86$

$80-0.01y=86$

$6=-0.01y$

$=-600$

Subsitude -600 for y in the first equation and solve for x.

$x-600=1000$

$x=1600$

-600 and 1600 were invested into the two accounts.

4 0

2 years ago

Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i

jenyasd209 [6]

Answer:

If the limit that you want to find is $\lim_{x\to \infty}\dfrac{P(x)}{Q(x)}$ then you can use the following proof.

Step-by-step explanation:

Let $P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0}$ and $Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0}$ be the given polinomials. Then

$\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}$

Observe that

$\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}$

and

$\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}$

Then

$\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}$

3 0

3 years ago

If s(x) = x – 7 and t(x) = 4x2 – x + 3, which expression is equivalent to (t*s)(x) ?

Inessa05 [86]

Hello,

(t*s)(x)=t(x)*s(x)=(4x²-x+3)*(x-7)

Answer D

8 0

3 years ago

Read 2 more answers

How to factor out xsquared+6x-27

Aleks04 [339]

X^2 + 6x - 27
(x - 3)(x + 9)

The answer is: (x - 3)(x + 9).

5 0

3 years ago