Answer:
I HOPE THE ABOVE INFORMATION WILL HELP YOU A LOT.
HAVE A NICE DAY.
<span>The </span>standard enthalpy of formation<span> <span>is defined as the change in </span></span>enthalpy<span> <span>when one mole of a substance in the </span></span>standard<span> <span>state (1 atm of pressure and temperature of 298.15
K) is </span></span>formed<span> <span>from its
pure elements under the same conditions.</span></span>
It runs from 0 to 14. (A)
It is based off the -log [H+] where [H+] is the concentration of the Hydrogen ions.
Answer:
1290 atm
Explanation:
P1V1=P2V2
P2= (P1V1)/V2
P2=(2.15 atm * 750 mL)/(1.25 mL)
P2=1290 atm