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Burka [1]
3 years ago
7

2. Which one of the following chemical equations is balanced? A. 2NaCl + H2SO4 → HCL + NaSO4 B. NH3 + H2O → 2NH4OH C. 2Na + S →

2NaS D. KOH + H2SO4 → KHSO4 + H2O
Chemistry
2 answers:
Lady_Fox [76]3 years ago
6 0
D.  KOH + H₂SO₄ → KHSO₄ + H₂O
vladimir2022 [97]3 years ago
4 0
Its D. KOH+H2SO4---->KHSO4+H2O
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The notation for a particular nucleus is r3785b. in an electrically neutral atom. How many electrons are in orbit about this nuc
Serhud [2]

^{85}_{37}Rb has 37 electrons in the orbit about its nucleus.

<h3>How to write an atomic symbol with atomic mass and atomic number?</h3>

Atomic mass is the total number of neutrons and protons present in the nucleus of an element.

The atomic number is the total number of protons present in the nucleus of an element.

For writing an atomic symbol, atomic mass is written on the top left of the atomic symbol, and the atomic number is written on the downside of the left of the symbol.

^{Atomic mass}_{Atomic number}X

An electrically neutral atom is an atom that has an equal number of electrons as well as protons.

Thus from the above conclusion we can say that  ^{85}_{37}Rb has 37 electrons.

Learn more about Atomic mass and atomic number here:

brainly.com/question/3187640

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3 0
2 years ago
J.j thomson a british physicist was the first to identify the
Shalnov [3]
<span>J.j thomson a british physicist was the first to identify the electron in 1987</span>
5 0
3 years ago
What amount of energy is required to change a spherical drop of water with a diameter of 1.80 mm to three smaller spherical drop
Gekata [30.6K]
This is a straightforward question related to the surface energy of the droplet. 

<span>You know the surface area of a sphere is 4π r² and its volume is (4/3) π r³. </span>

<span>With a diameter of 1.4 mm you have an original droplet with a radius of 0.7 mm so the surface area is roughly 6.16 mm² (0.00000616 m²) and the volume is roughly 1.438 mm³. </span>

<span>The total surface energy of the original droplet is 0.00000616 * 72 ~ 0.00044 mJ </span>

<span>The five smaller droplets need to have the same volume as the original. Therefore </span>

<span>5 V = 1.438 mm³ so the volume of one of the smaller spheres is 1.438/5 = 0.287 mm³. </span>

<span>Since this smaller volume still has the volume (4/3) π r³ then r = cube_root(0.287/(4/3) π) = cube_root(4.39) = 0.4 mm. </span>

<span>Each of the smaller droplets has a surface area of 4π r² = 2 mm² or 0.0000002 m². </span>

<span>The surface energy of the 5 smaller droplets is then 5 * 0.000002 * 72.0 = 0.00072 mJ </span>
<span>From this radius the surface energy of all smaller droplets is 0.00072 and the difference in energy is 0.00072- 0.00044 mJ = 0.00028 mJ. </span>

<span>Therefore you need roughly 0.00028 mJ or 0.28 µJ of energy to change a spherical droplet of water of diameter 1.4 mm into 5 identical smaller droplets. </span>
7 0
3 years ago
Under the same conditions of temperature and pressure, which of the following gases would behave most like an ideal gas?Ne, N₂,
malfutka [58]

Answer:

Ne

Explanation:

Atomic number of Ne is 10.

Electronic configuration of Ne:

1s^2 2s^2 2p^6

Octet of Ne is complete . Element having complete octet are stable and behave ideal gas.

N_2 and CH_4 are reactive and hence, does not behave as ideal gas.

3 0
3 years ago
Write balance complete molecular equation, ionic equation, and net ionic equations for the reactions that occur when each of the
AveGali [126]

<u>Answer:</u> The complete molecular, ionic, and net ionic equations are given below. The spectator ions are sodium and nitrate ions.

<u>Explanation:</u>

The ionic equation is defined as the equation in which all the substances that are strong electrolytes present in an aqueous state and are represented in the form of ions.

The net ionic equation is defined as the equations in which spectator ions are not included.

Spectator ions are the ones that are present equally on the reactant and product sides. They do not participate in the reaction.

The balanced molecular equation for the reaction of lead (II) nitrate and sodium sulfide follows:

Pb(NO_3)_2(aq)+Na_2S(aq)\rightarrow PbS(s)+2NaNO_3(s)

The ionic equation follows:

Pb^{2+}(aq)+2NO_3^-(aq)+2Na^+(aq)+S^{2-}(aq)\rightarrow PbS(s)+2Na^+(aq)+2NO_3^-(aq)

As sodium and nitrate ions are present on both sides of the reaction. Thus, they are considered spectator ions.

The net ionic equation follows:

Pb^{2+}(aq)+S^{2-}(aq)\rightarrow PbS(s)

3 0
3 years ago
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