Because when the orange frog eats the red fly the dye that make the fly red turns the frog red very slowly
Divide both sides to get 104 and that’s your answer
Hey there :)
<em>Q</em><em>u</em><em>e</em><em>s</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em><em> </em><em>How many km are in 5.6mm? </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>3 </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>-6 </em>
<em>=</em><em>></em><em>5.6x10</em><em>^</em><em>-3 </em>
<em>=</em><em>></em><em> </em><em>5.6x10</em><em>^</em><em>6</em>
<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>:</em><em>-</em>

<em>E</em><em>x</em><em>p</em><em>l</em><em>a</em><em>n</em><em>a</em><em>t</em><em>i</em><em>o</em><em>n</em><em>:</em><em>-</em>
By using the formula-

As 1 with 6 zeros, we convert it into exponential form.

As this above value is fraction type, we can do the reciprocal, thus, the exponent gets a negative value.

Now combine with given question.

A saturated solution is one in which no more solute is able to dissolve in a given solvent at a particular temperature. Some amount of the solute is left undissolved in the solution.
Unsaturated solution has solute in lower proportions than required to form a saturated solution.
Supersaturated solution has solute in amounts greater than a saturated solution.
We can take the help of solubility curve in order to find out the amount of a salt required to prepare a saturated solution of that salt at a particular temperature.
The solubility of KI at 10
is 136 g/ 100 mL water
The solubility of
at
is 21 g/100 mL water.
The solubility of
at
is 80 g/100 mL water.
The solubility of NaCl at
is 38 g/ 100 mL water.
So the correct answer will be KI, as it would need 136 g KI / 100 mL water to form a saturated solution at
.So, if we have 80g KI/ 100mL water it would be an unsaturated solution.