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Vitek1552 [10]
3 years ago
14

Draw three different Lewis structures that could be possible for ZX2, assuming that Z is the central atom and that X is not hydr

ogen. Both Z and X obey the octet rule. Give molecular shapes and bond angles for each structure drawn. In each case, use valence shell electron pair repulsion theory to explain why the molecular shape is possible.
Chemistry
1 answer:
Mariana [72]3 years ago
3 0

Answer:

See images attached and explanation

Explanation:

I have drawn three possible structures of ZX2. We have to remember that the shapes of molecules could be predicted on the basis of the Valence shell electron pair repulsion theory.

The number of electrons on the valence shell of the central atom determines the shape of the molecule. We have also been told that X is not hydrogen.

If the two X atoms are arranged at a bond angle of 180 degrees, we could have either structure I or II. We will have these structures if the Z atom is sp2 hybridized.

Similarly, if the Z atom is sp3 hybridized, we may have structure III in which the molecule is bent with a bond angle less than 109 degrees. This may result from the presence of a lone pair on Z.

Note that all these structures obey the octet rule.

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4 years ago
In the reaction between Lithium Sulfate and an excess of Lead (II) Nitrate, how many molecules of Lithium Nitrate can be expecte
siniylev [52]

Answer:

1.46x10^{23}molecules \ LiNO_3

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

Li_2SO_4 + Pb(NO_3)_2 \rightarrow PbSO_4+2LiNO_3

Thus, since lead (II) nitrate is in excess, we can directly compute the moles of lithium nitrate by applying the 1:2 molar ratio between them in the chemical reaction as well as the molar mass of Lithium Sulfate that is 110 g/mol for the stoichiometric shown below factor:

n_{LiNO_3}=13.3gLi_2SO_4*\frac{1molLi_2SO_4}{110gLi_2SO_4} *\frac{2molLiNO_3}{1molLi_2SO_4} =0.242molLiNO_3

Finally, by using the Avogadro's number we are able to compute the molecules:

0.242molLiNO_3*\frac{6.022x10^{23}molecules\ LiNO_3}{1mol}=1.46x10^{23}molecules \ LiNO_3

Best regards.

5 0
4 years ago
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Calculate the number of moles in 9.22 X 10^23 atom iron
sveta [45]
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2 years ago
For this question, the "entropy term" refers to "-TΔS". Addition reactions are generally favorable at low temperatures because _
nata0808 [166]

Answer:

Lowering the temperature typically reduces the significance of the decrease in entropy. That makes the Gibbs Free energy of the reaction more negative. As a result, the reaction becomes more favorable overall.  

Explanation:

In an addition reaction there's a decrease in the number of particles. Consider the hydrogenation of ethene as an example.

\rm H_2C\text{=}CH_2\; (g) + H_2\; (g) \stackrel{\text{Ni}^\ast}{\to} H_3C\text{-}CH_3\; (g).

When \rm H_2 is added to \rm H_2C\text{=}CH_2 (ethene) under heat and with the presence of a catalyst, \rm H_3C\text{-}CH3 (ethane) would be produced.

Note that on the left-hand side of the equation, there are two gaseous molecules. However, on the right-hand side there's only one gaseous molecule. That's a significant decrease in entropy. In other words, \Delta S < 0.

The equation for the change in Gibbs Free Energy for a particular reaction is:

\Delta G = \Delta H + (\underbrace{- T \, \Delta S}_{\text{entropy}\atop \text{term}}).

For a particular reaction, the more negative \Delta G is, the more spontaneous ("favorable") the reaction would be.

Since typically \Delta S < 0 for addition reactions, the "entropy term" of it would be positive. That's not very helpful if the reaction needs to be favorable.

T (absolute temperature) is always nonnegative. However, lowering the temperature could help bring the value of

8 0
3 years ago
Please help
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5 0
3 years ago
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