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yarga [219]
3 years ago
11

How many protons, neutrons, and electrons does 35/17 Cl ^ 1- have?

Chemistry
1 answer:
Alex Ar [27]3 years ago
8 0

Answer:

In accordance to the pic

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The average sedentary male will achieve a VO2 max of approximately 35 to 40 mL/Kg/min. And the average sedentary female will score a VO2 max of between 27 an 30 mL/Kg/min.
6 0
3 years ago
In humans, glucose may be the product of chemical digestion when what kinds of foods are eaten? A) carbohydrates like bread B) f
forsale [732]
<h3>Answer:</h3>

Carbohydrates like bread

<h3>Explanation:</h3>
  • Chemical digestion involves the breakdown of food molecules by the use of enzymes to generate simpler molecules that can be absorbed into the body's metabolism.
  • During chemical digestion, carbohydrates are broken down into simple molecules such as glucose which can be easily absorbed in the small intestines.
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4 0
4 years ago
Una sola dosis de etanol, C2 H5 OH, eleva el nivel intracelular de iones calcio. Los iones Ca2+ liberados por el etanol 0,10 M m
11Alexandr11 [23.1K]

Answer:

No se bro cual se la respuesta .......

Explanation:

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4 0
3 years ago
Calculate the number of atoms of carbon present in 25 g of CACO3 ?​
stiks02 [169]

1.506 × 10²³ carbon atoms

Explanation:

First we calculate the number of moles of calcium carbonate (CaCO₃) contained in 25 g.

number of moles = mass / molecular weight

number of moles of CaCO₃ = 25 / 100 = 0.25 moles

Now we make use of Avogadro's number which tell us that we have 6.022 × 10²³ molecules (or atoms) in one mole of substance.

Now in our case:

if in         1 mole of CaCO₃ we have 1 × 6.022 × 10²³ carbon atoms

then in   0.25 moles  of CaCO₃ we have X carbon atoms

X = (0.25 × 1 × 6.022 × 10²³) / 1

X = 1.506 × 10²³ carbon atoms

Learn more:

Avogadro's number

brainly.com/question/1445383

7 0
3 years ago
Calculate the no. of each atoms presents in 10 grams of calcium carbonate.
raketka [301]

Molar Mass of Calcium carbonate:-

\\ \sf\longmapsto CaCO_3

\\ \sf\longmapsto 40u+12u+3(16u)

\\ \sf\longmapsto 52u+48u

\\ \sf\longmapsto 100u

\\ \sf\longmapsto 100g/mol

  • Given Mass=10g

\boxed{\sf No\:of\;moles=\dfrac{Given\:Mass}{Molar\:Mass}}

\\ \sf\longmapsto No\:of\;moles=\dfrac{10}{100}

\\ \sf\longmapsto No\:of\:moles=0.1mol

Now

\boxed{\sf No\:of\:molecules=No\;of\:moles\times Avagadro\: No}

\\ \sf\longmapsto 0.1\times 6.023\times 10^{23}

\\ \sf\longmapsto 6.023\times 10^{22}molecules

8 0
3 years ago
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