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Masja [62]
3 years ago
12

A piece of iron block moves across a rough horizontal surface before coming to rest. The mass of the block is 1.3 kg, and its in

itial speed is 4.0 m/s. How much does the block's temperature increase, if it absorbs 71% of its initial kinetic energy as internal energy? The specific heat of iron is 452 J/(kg · °C).
Physics
1 answer:
KengaRu [80]3 years ago
6 0

Answer:

0.0126°C

Explanation:

Kinetic energy sustain by the block,K.E = 1/2× mass×velocity^2

K.E = 1/2 ×1.3×(4^2)

=1/2 × 1.3× 16 = 1.3 ×8 = 10.4J

The internal energy is 71% of kinetic energy is;

U= 71/100 × 10.4 = 7.38J

But U = m × C × ∆T

Where U is internal energy

m is the mass of iron

C is the heat capacity of iron

∆T is the temperature change

By make ∆T the subject of the formula we have

∆T=U/ m×C

=7.38/ 1.3×452= 0.0126°C

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2 years ago
Please help me find the answer ​
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Answer:

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27) 500 N

Explanation:

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26.b) Mechanical advantage is the ratio between the forces:

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Efficiency is the ratio between the work:

e = work done on load / work done by effort

Work is force times distance.

e = (F load × d load) / (F effort × d effort)

Rearranging:

e = (F load / F effort) × (d load / d effort)

e = MA × (d load / d effort)

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27) In a three pulley system, the load moves a third of the distance of the effort.

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0.40 = (600 N / F) × (1/3)

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Here,

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Voltage = ?

Now,

R = V/A

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I hope it's help you...

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