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Igoryamba
3 years ago
5

The top floor of the Ostankino TV Tower in Moscow is located at a height of 360.4 m. Assume a stone is dropped from this top flo

or. [Note: round your numerical answers to two decimal places; if necessary]
(a) Find the distance of the stone above the ground at any time t (before it hits the ground)

(b) How long does it take the stone to reach the ground?

(c) With what velocity does it reach the ground?
Physics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

x=360.4-4.905t^2

8.57181 s

84.0894561 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Let distance from ground be x

From equation of motion we have

s=ut+\frac{1}{2}at^2

Here, distance covered while the stone is falling will be 360.4-x

360.4-x=ut+\frac{1}{2}at^2\\\Rightarrow 360.4-x=\frac{1}{2}9.81t^2\\\Rightarrow 360.4-x=4.905t^2\\\Rightarrow x=360.4-4.905t^2

The equation is x=360.4-4.905t^2

At the ground x = 0

0=360.4-4.905t^2\\\Rightarrow t=\sqrt{\dfrac{-360.4}{-4.905}}\\\Rightarrow t=8.57181\ s

The time taken by the stone to fall to the ground is 8.57181 s

v=u+at\\\Rightarrow v=0+9.81\times 8.57181\\\Rightarrow v=84.0894561\ m/s

The velocity of the stone when it reaches the ground is 84.0894561 m/s

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Answer:

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Momentum of Center of mass MVcom  is sum of both blocks momentum and is given by

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Where

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Putting values, we get;

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<h3>Answer</h3><h3>7 Ns</h3><h3>Explanation</h3>

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mass of foul ball = 0.140 kg

initial speed with which ball was hit with the bat = 30 m/s

final speed  = 40 m/s

According to the scenario the whole scene is making a right angle triangle

So, to the solve the question we will use pythagorus theorem

<h3>Hypotenuse² = base² + height²</h3>

Here,

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Base = 1st change of momentum

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1st impulse (1st change of momentum)

p = m(1)v(1) = (0.14 kg)(40.0 m/s) = 5.6 kg m / s = 5.6 N s

2nd impulse (2nd change of momentum)

p = m(2)v(2) = (0.14 kg)(30.0 m/s) = 4.2 kg m / s = 4.2 N s

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A bowling ball accidentally falls out of the cargo bay of an airliner as it flies along in a horizontal direction. As seen from
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The path the bowling ball would most closely follow after leaving the airplane is horizontal direction.

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The bowling ball will maintain the path of the airline in the first few seconds of fall, after which it will change its path to vertical direction.

Thus, the path the bowling ball would most closely follow after leaving the airplane is horizontal direction.

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3 0
2 years ago
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Answer:

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Where;

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Ф = phase difference between voltage and current.

<u><em>Now,</em></u>

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7 0
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