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Igoryamba
3 years ago
5

The top floor of the Ostankino TV Tower in Moscow is located at a height of 360.4 m. Assume a stone is dropped from this top flo

or. [Note: round your numerical answers to two decimal places; if necessary]
(a) Find the distance of the stone above the ground at any time t (before it hits the ground)

(b) How long does it take the stone to reach the ground?

(c) With what velocity does it reach the ground?
Physics
1 answer:
Ulleksa [173]3 years ago
8 0

Answer:

x=360.4-4.905t^2

8.57181 s

84.0894561 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

g = Acceleration due to gravity = 9.81 m/s² = a

Let distance from ground be x

From equation of motion we have

s=ut+\frac{1}{2}at^2

Here, distance covered while the stone is falling will be 360.4-x

360.4-x=ut+\frac{1}{2}at^2\\\Rightarrow 360.4-x=\frac{1}{2}9.81t^2\\\Rightarrow 360.4-x=4.905t^2\\\Rightarrow x=360.4-4.905t^2

The equation is x=360.4-4.905t^2

At the ground x = 0

0=360.4-4.905t^2\\\Rightarrow t=\sqrt{\dfrac{-360.4}{-4.905}}\\\Rightarrow t=8.57181\ s

The time taken by the stone to fall to the ground is 8.57181 s

v=u+at\\\Rightarrow v=0+9.81\times 8.57181\\\Rightarrow v=84.0894561\ m/s

The velocity of the stone when it reaches the ground is 84.0894561 m/s

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3 years ago
a force vector f has a magnitude of 12.0 n. it is oriented 60° to the left of the y ax what are its x and y components?
Arte-miy333 [17]

The  force vector that has a magnitude of 12.0 N. and is oriented 60° to the left of the (y) has the followings components:

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To solve this exercise the formulas and procedures we will use are:

  • v(x) = v * cosine (angle)
  • v(y) = v * sine (angle).

Where:

  • v= magnitude of the vector
  • v(x) = component of the vector on the (x) axis
  • v(y) = component of the vector on the (y) axis
  • angle = angle

Information about the problem:

  • angle = 60º
  • v = 12.0 N
  • v(x)= ?
  • v(y)= ?

Applying the formula of the component of the vector in the (x) axis we have:

v(x) = v * cosine (angle).

v(x) = 12.0 N * cosine (60º)

v(x) =6 N

Applying the formula of the component of the vector in the (y) axis we have:

v(y) = v * sine (angle)

v(y) = 12.0 N * sine (60º)

v(y) = 10.39 N

<h3>What is a vector?</h3>

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5 0
1 year ago
A 2-m long string is stretched between two supports with a tension that produces a wave speed equal to vw=50.00m/s. What are the
svetoff [14.1K]

Answer

given,

Length of the string, L = 2 m

speed of the wave , v = 50 m/s

string is stretched between two string

For the waves the nodes must be between the strings

the wavelength  is given by

           \lambda = \dfrac{2L}{n}

where n is the number of antinodes; n = 1,2,3,...

the frequency expression is given by

            f = n\dfrac{v}{2L}

now, wavelength calculation

      n = 1

           \lambda_1 = \dfrac{2\times 2}{1}

                    λ₁ = 4 m

      n = 2

           \lambda_2 = \dfrac{2\times 2}{2}

                   λ₂ = 2 m

      n =3

           \lambda_3 = \dfrac{2\times 2}{3}

                    λ₃ = 1.333 m

now, frequency calculation

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            f = n\dfrac{v}{2L}

            f_1 =1\times \dfrac{50}{2\times 2}

                    f₁ = 12.5 Hz

      n = 2

            f = n\dfrac{v}{2L}

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                    f₂= 25 Hz

      n = 3

            f = n\dfrac{v}{2L}

            f_3 =3\times \dfrac{50}{2\times 2}

                    f₃ = 37.5 Hz

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bagirrra123 [75]

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