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3 years ago

11

(03.04 MC) What is the formula for sodium nitrite? O NaN O NaN O NaNO2 O NaNO3

2 answers:

charle [14.2K]3 years ago

7 0

Answer:

NaNO2 is the formula for sodium nitrite

Explanation:

Check the selected ions chart to find out more in depth.

Degger [83]3 years ago

3 0

Answer:

Formula for sodium nitrite is NaNO₂

Explanation:

Sodium nitrite is an inorganic compound with the chemical formula NaNO₂. It is a white to slightly yellowish crystalline powder that is very soluble in water and is hygroscopic.

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What is a short description of oxygenated blood flow ?

lubasha [3.4K]

the portion of the circulatory system which carries deoxygenated blood<span> away from the right ventricle of the heart, to the lungs, and returns </span>oxygenated blood<span> to the left atrium and ventricle of the heart. I hope this helps, good luck. </span>

6 0

3 years ago

Read 2 more answers

To aid in the prevention of tooth decay, it is recommended that drinking water contains 0.900 ppm fluoride (F-). A) How many g o

Romashka-Z-Leto [24]

Answer:

a) <u>1.740 g</u> of F- must be added to a cylindrical water reservoir

b) Grams of sodium fluoride, NaF, that contain this much fluoride:

3.84 g

Explanation:

Step 1. calculate the volume of the tank:

Volume of cylinder =

$\pi r^{2}h$ ,

Here r = radius of the cylinder = d/2

h = depth = 21.80m

$r=\frac{d}{2}$

$=\frac{3.36x10^{2}}{2}$

= 168 m

Volume =

$=\frac{22\times 168^{2}\times 21.80}{7}$

$=1.93\times 10^{6} m^{3}$

2.Convert ppm to g/m3 and Solve for mass of F-

$1ppm = 1g/m^{3}$

$0.9ppm = 0.9g/m^{3}$

Because both ppm and g/m3 are same quantity .

$g/m^{3} =\frac{mass\ of\ F-(g)}{Volume\ m^{3}}\times 10^{6}$

$0.9 =\frac{mass\ of\ F-}{1.93\times 10^{6} m^{3}}\times 10^{6}$

$mass\ of\ F- =1.740g$

mass of F- required = 1.740 g

3. Apply <u>mole concept </u>to calculate grams of sodium fluoride produced

mass of 1 mole of F2 = 38 g

mass of 1 mole of NaF = 42 g

(from periodic table calculate molar mass)

$2Na+F_{2}\rightarrow 2NaF$

Here 1 mole of F2 produce = 2 mole of NaF

So,

38 g of F2 produce = 2 x 42 g of NaF

38 g of F2 produce = 84 g of NaF

1 g of F2 produce = 84/38 g of NaF

1.74 g F2 produce =

$\frac {84}{38}\times 1.74$

1.74 g F2 produce = 3.84 g of NaF

3.84 g of NaF is produced

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3 years ago

HELPPPPPP! PLEASE ASAPPPPPPPPPPPP!?

stiv31 [10]

answer:

millions of animals..

hope my ans helps

please give brainliest to my answer

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3 0

3 years ago

lesya692 [45]

Explanation:

c Silver is an excellent conductor

hope it helps!

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2 years ago

Read 2 more answers

1. A 1500kg car is being lifted by a hydraulic jack attached to a flat plate. Underneath the plate is

AURORKA [14]

Answer:

the pressure in the pipe in the case when there is no net force on the car is 81,726 N/m^2

Explanation:

a. The computation of the pressure in the pipe in the case when there is no net force on the car is shown below

As we know that

Pressure = F ÷ area

Also

F = mg

Now

= (1500 × 9.8) ÷π (0.24)^2

= 81,726 N/m^2

Hence, the pressure in the pipe in the case when there is no net force on the car is 81,726 N/m^2

5 0

3 years ago