A pendulum is raised to a height of 0.3m above its lowest point and released. What is the velocity of the pendulum at its lowest
1 answer:
Answer:
v = 2,425 m / s
Explanation:
A simple pendulum has anergy stored at the highest point of the path and this energy is conserved throughout the movement.
highest point
Em₀ = U = m g y
lowest point
= K = ½ m v²
Em₀ = Em_{f}
mg y = ½ m v²
v = √ 2gy
let's calculate
v = √ (2 9.8 0.3)
v = 2,425 m / s
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Answer:
Charge of the sphere =
Charge of the rod =
Explanation:
Parameters given:
Initial charge of sphere = 8.11 nC =
Initial charge of rod = -6.13 nC =
In the process, the rod lost . We have to find the charge of these electrons. Then, we subtract it from the rod's initial charge to get its final charge and add it to the sphere's initial charge to get its final charge.
Charge of electrons = electronic charge * number of electrons
=
=
FINAL CHARGE OF ROD
Final charge of rod = - (
)
=
FINAL CHARGE OF SPHERE
Final charge of sphere = + (
)
=