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Rzqust [24]
3 years ago
10

What volume will be occupied by 11.7 g of Helium in a balloon at an altitude of 10.0 km if the air pressure is 0.262 atm and the

temperature is -50.0 °C?
Chemistry
1 answer:
matrenka [14]3 years ago
6 0

Answer: 204 L

Explanation:

According to ideal gas equation:

PV=nRT

P = pressure of gas = 0.262 atm

V = Volume of gas = ?

n = number of moles = \frac{\text {given mass}}{\text {molar mass}}=\frac{11.7g}{4g/mol}=2.92

R = gas constant =0.0821Latm/Kmol

T =temperature =-50^0C=(273+(-50))K=223K

V=\frac{nRT}{P}

V=\frac{2.92\times 0.0820 L atm/K mol\times 223K}{0.262atm}=204L

Thus volume occupied by 11.7 g of Helium in a balloon is 204L

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