Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
Solution : Given,
Mass of Cu = 300 g
Molar mass of Cu = 63.546 g/mole
Molar mass of 
= 183.511 g/mole
- First we have to calculate the moles of Cu.
The moles of Cu = 4.7209 moles
From the given chemical formula, we conclude that the each mole of compound contain one mole of Cu.
So, The moles of Cu = Moles of = 4.4209 moles
- Now we have to calculate the mass of .
Mass of = Moles of × Molar mass of = 4.4209 moles × 183.511 g/mole = 866.337 g
Mass of = 866.337 g = 0.8663 Kg (1 Kg = 1000 g)
Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.
<span>Scientific knowledge
can be gained through experiment by doing a thorough experimental procedure
that will enable to answer the objectives of the experiment that will lead to a
scientific knowledge. Through experimentation you can know the behavior of a
variable with respect to a certain variable. This can also answer some
knowledge gap about certain topic</span>
A product...............................................................
Answer:
none.
Explanation:
if we are not given any value as temperature in the question. and we were asked to calculate the T1, then our T2 will be 273k.
Answer:
Explanation:
pressure(volume)=Number of moles(constant)(tempature)
(88.4 kPa) (344 mL) =N(0.0821)(85C)
all you need to do from here is convert to SI units (kelvin, liter, pascal) and solve for n
if you leave it as it you get N=4357.61266
converting it gives a number a little closer to N=0.01024061 (used a ideal gas law calculator to doble check the math lol)
Hope this helps!!
