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Flura [38]
3 years ago
13

Why would the presence of oxygen bubbles be a good indicator of photosynthesis occurring?

Chemistry
1 answer:
irina1246 [14]3 years ago
6 0

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How many moles are in 55.98g CF2Cl2
Karolina [17]
No of moles = given mass ÷ molecular mass
n = 55.98 ÷ (12+19×2+35.5×2)
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3 years ago
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For the reaction 2NOCl(g) <-----> 2NO(g) + Cl2(g), Kc = 8.0 at a certain temperature. What concentration of NOCl must be p
Nat2105 [25]
Answer is: <span>concentration of NOCl is 3.52 M.
</span>
Balanced chemical reaction: 2NOCl(g) ⇄ 2NO(g) + Cl₂<span>(g).
Kc = 8.0.
</span>[NOCl] = 1.00 M; equilibrium concentration.
[NO] = x.
[Cl₂] = x/2; equilibrium concentration of chlorine.<span>
Kc = </span>[Cl₂] ·[NO]² / [NOCl].
8.00 = x/2 · x² / 1.
x³/2 = 8.
x = ∛16.
x = 2.52 M.
co(NOCl) = [NOCl] + x.
co(NOCl) = 1.00 M + 2.52 M.
co(NOCl) = 3.52 M; the initial concentration of NOCl.


7 0
2 years ago
Describe how to test your unknown salt mixture for the presence of<br>Na3PO4.12H2O.​
klemol [59]

Na3PO4*12H2O + BaCl2*2H2O = Ba3(PO4)2 + NaCl + H2O

add barium chloride to your Na3PO4.12H2O a white precipitate of Ba3(PO4)2 will be formed wrt salt(NaCl) and water(H20) if Na3PO4.12H2O. will be there.

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3 years ago
How could you determine the acceleration of marble?
arsen [322]
Since f=ma assuming you knew the mass of the marble and the total amount of force acting on it than you would divide the amount of force by the mass.
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3 years ago
During early research in nuclear energy, why were scientists surprised that the products from splitting a uranium nucleus had le
creativ13 [48]
Scientists expected that the law of conservation of mass would apply to nuclear fission in terms of the masses of the subatomic particles. In reality, the mass of an atom is not equal to the sum of the masses of the subatomic particles that make it up. This is because of the energy that binds the subatomic particles. This energy has mass and when the bond is broken, the mass of the energy of the bonds is lost resulting to what we now cal, a mass defect.
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3 years ago
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