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3 years ago

How many moles of CO2 would be present in a gas sample of 10 L at 25.0oC and a pressure of .77 atm?

1 answer:

4 0

Use PV=nRT to solve the equation. You need to solve for n (number of moles). Don’t forget to convert the temperature to kelvins by adding 25+273. Use 0.082057 for R.

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A gas has a pressure of 3.16 atm at STP. I have decided to transfer it to a container that is 3 times larger than the original v

Oliga [24]

Answer:

The new pressure is 1.0533 atm

Explanation:

According to Boyle's Law : The Pressure of fixed amount of gas is inversely proportional to Volume at constant temperature.

PV = Constant

P1V1 = P2V2

$P_{1}V_{1}=P_{2}V_{2}$ .....(1)

P1 = 3.16 atm

Accprding to question ,

V1 = V

V2 = 3 V

Insert the value of V1 , V2 and P1 in the equation(1)

$P_{1}V_{1}=P_{2}V_{2}$

$3.16\times V=P_{2}\times 3V$

V and V cancel each other

$3.16=P_{2}\times 3$

$P_{2}=\frac{3.16}{3}$

$P_{2}=1.05atm$

5 0

3 years ago

At 50 degrees celcius and standard pressure intermolecular forces of attraction are strongest in a sample of

Ivanshal [37]

At 50 degrees Celsius and standard pressure inter-molecular forces of attraction are strongest in a sample of ethanoic acid.
Ethanoic acid has hydrogen atom bonded with a more electronegative atom; Oxygen. As a result, the molecule possesses strong intermolecular Hydrogen Bonds. Therefore; ethanoic acid, and all other carboxyllic acids have the tendency to form dimers.

4 0

3 years ago

Read 2 more answers

What is clch2ch2ch2oh when oxidized?

Maksim231197 [3]

The first step of the oxidation of a primary alcohol involves conversion to an aldehyde via the elimiination of a hydrogen molecule. Thus, ClCH2CH2CH2OH becomes ClCH2CH2COH, which is 3-chloropropanal.

5 0

3 years ago

A fusion reaction takes places between carbon and another element. Neutrons are realeased, and a different element is formed. Th

Ymorist [56]

Hydrogen is the new element

6 0

3 years ago

A solution of hydrocloric acid has a molarity of 2.25 M HCl. If a reaction requires 5.80 g of HCI, what

Natali [406]

Answer:

0.071L

Explanation:

From the question given, we obtained the following data:

Molarity of HCl = 2.25 M

Mass of HCl = 5.80g

Molar Mass of HCl = 36.45g/mol

Number of mole of HCl =?

Number of mole = Mass /Molar Mass

Number of mole of HCl = 5.8/36.45 = 0.159mole

Now, we can obtain the volume required as follows:

Molarity = mole /Volume

Volume = mole /Molarity

Volume = 0.159mole/ 2.25

Volume = 0.071L

4 0

3 years ago