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Goryan [66]
3 years ago
8

How many moles of CO2 would be present in a gas sample of 10 L at 25.0oC and a pressure of .77 atm?

Chemistry
1 answer:
Step2247 [10]3 years ago
4 0
Use PV=nRT to solve the equation. You need to solve for n (number of moles). Don’t forget to convert the temperature to kelvins by adding 25+273. Use 0.082057 for R.
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you need to prepare 250.0 mL of a 1.50 M HCl solution from a 2.00 M HCl stock solution. assuming that the accuracy of the concen
Savatey [412]

Answer:

I should use a volumetric flask.

Explanation:

If the accuracy of the concentration is important, we need to use a volumetric flask.

7 0
2 years ago
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Name the following ester molecule:OA. ethyl butanoateB. propyl pentanoateC. methyl heptanoateD. methylpropanoate
disa [49]

Answer

A. ethyl butanoate

Explanation:

Esters are known for their distinctive odors and are commonly used for food aroma and fragrances. The general formula of an ester is RCOOR'.

Esters are formed through reactions between an acid and an alcohol with the elimination of water.

Esters are named as if the alkyl chain from the alcohol is a substituent. No number is assigned to this alkyl chain. This is followed by the name of the parent chain from the carboxylic acid part of the ester with an –e remove and replaced with the ending –oate.

Hence, the name of the given ester is:

A. ethyl butanoate

8 0
1 year ago
Magnesium is the limiting reactant in this experiment. Calculate the theoretical yield of MgO for each trial.
liq [111]

/watch?v=DLzxrzFCyOs

6 0
2 years ago
What happens when salt water freezes.
inysia [295]

Answer:

salt water freezes just like fresh water, but at lower temperatures. Fresh water freezes at 32 degrees Fahrenheit but seawater freezes at about 28.4 degrees Fahrenheit , because of the salt in it. When salt water freezes, however, the ice contains very little salt because only the water part freezes.

7 0
3 years ago
A 2.60 g sample of titanium metal chemically combines
san4es73 [151]

<u>Answer:</u>

<u>For a:</u> The empirical formula for the given compound is TiCl_4

<u>For b:</u> The percent by mass of titanium and chlorine in the sample is 25.55 % and 74.78 % respectively.

<u>Explanation:</u>

  • <u>For a:</u>

We are given:

Mass of Titanium = 2.60 g

Mass of sample = 10.31 g

Mass of Chlorine = 10.31 - 2.60 = 7.71 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of titanium =\frac{\text{Given mass of Titanium}}{\text{Molar mass of Titanium}}=\frac{2.60g}{47.867g/mole}=0.054moles

Moles of Chlorine = \frac{\text{Given mass of Chlorine}}{\text{Molar mass of Chlorine}}=\frac{7.71g}{35.5g/mole}=0.217moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.054 moles.

For Titanium = \frac{0.054}{0.054}=1

For Chlorine  = \frac{0.217}{0.054}=4.01\approx 4

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of Ti : Cl = 1 : 4

Hence, the empirical formula for the given compound is TiCl_4

  • <u>For b:</u>

To calculate the percentage by mass of substance in sample, we use the equation:

\%\text{ composition of substance}=\frac{\text{Mass of substance}}{\text{Mass of sample}}\times 100       .......(1)

  • <u>For Titanium:</u>

Mass of sample = 10.31 g

Mass of titanium = 2.60 g

Putting values in above equation, we get:

\%\text{ composition of titanium}=\frac{2.60g}{10.31g}\times 100=25.22\%

  • <u>For Chlorine:</u>

Mass of sample = 10.31 g

Mass of chlorine = 7.71 g

Putting values in above equation, we get:

\%\text{ composition of chlorine}=\frac{7.71g}{10.31g}\times 100=74.78\%

Hence, the percent by mass of titanium and chlorine in the sample is 25.55 % and 74.78 % respectively.

7 0
2 years ago
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