Question

How many molecules are in 49.0 g of H2SO4? Answer in units of molec.

Answer 1

Answer:

= 3.01× $10^{23}$ molecules.

Explanation:

1 mole of $H_{2}SO_{4}$ - 98g

? moles of $H_{2}SO_{4}$ - 49g

= 49 ÷ 98 = 0.5 moles of O2 in 49g.

But 1 mole of any substance = 6.023 × $10^{23}$ molecules

∴ 0.5 moles = 0.5 × 6.023 × $10^{23}$ molecules

= 3.01× $10^{23}$ molecules.