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murzikaleks [220]
3 years ago
7

You are performing an experiment which requires you to add 2.00 grams of benzene to a reaction. Benzene has a density of 0.790 g

/mL. You should add:
a. 2.53 mL
b. 0.395 mL
c. 1.58 mL
d. 2.00 mL
Chemistry
2 answers:
Scorpion4ik [409]3 years ago
8 0

Answer:

a. 2.53 mL

Explanation:

Hello,

In this case, by knowing the density is defined as the ratio of the mass to the volume:

\rho =\frac{m}{V}

Since both the mass and density of benzene are given, we can easily compute the volume by solving for it:

V=\frac{m}{\rho}=\frac{2.00g}{0.790g/mL}\\  \\V=2.53mL

Therefore the answer is a. 2.53 mL .

Best regards.

____ [38]3 years ago
4 0

Answer:

a. 2.53 mL

Explanation:

The density is an intensive property, that is, it does not depend on the system size or the amount of material in the system. At a given temperature, the density of a liquid is constant, so it can be used to identify a substance.

The density (ρ) results from the quotient between the mass (m) of the liquid and its volume (V). We can use this expression to find the volume corresponding to 2.00 grams of benzene (ρ = 0.790 g/mL).

ρ = m / V

V = m / ρ

V = 2.00 g / (0.790 g/mL)

V = 2.53 mL

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BARSIC [14]

The number of C atoms in 0.524 moles of C is 3.15 atoms.

The number of SO_2 molecules in 9.87 moles  SO_2 is 59.43 molecules.

The moles of Fe in 1.40 x 10^{22} atoms of Fe is 0.23 x 10^{-1}

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<h3>What are moles?</h3>

A mole is defined as 6.02214076 × 10^{23} of some chemical unit, be it atoms, molecules, ions, or others. The mole is a convenient unit to use because of the great number of atoms, molecules, or others in any substance.

A. The number of C atoms in 0.524 mole of C:

6.02214076 × 10^{23} x 0.524 mole

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0.2324754694 x 10^{-1} moles.

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2.30x10^{24} ÷ 6.02214076 × 10^{23}

3.819239854 moles=3.81 moles

Learn more about moles here:

brainly.com/question/8455949

#SPJ1

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