Answer:
Explanation:
We have to make 100 mL 0f .405M HCl from 3 M solution of HCl .
volume of 3M to be taken required . Let this volume be V litre .
V litre of 3M will contain 3 V moles of HCl .
moles contained by 100 mL of ,405 HCl = .405 x .1 = .0405 moles .
So 3V = .0405
V = .0405 / 3 litre
= .0405 x 1000 / 4 mL
= 10.125 mL
So we have to take 10.125 mL of 3M HCl and add water to them to make its volume 100 mL .
1,2-dimbromopropane would be something like C which is the second best answer.
B would be correct if it had another carbon.
A is like C but incorrect for the same reason. 1,2-dibromoethane is what A is.
The answer has to be D where the bromines are right across from each other.
Answer:
See explanation and image attached
Explanation:
The Gilman reagent is a lithium and copper (diorganocopper) reagent with a general formula R2CuLi. R is an alkyl or aryl group.
They are useful in the synthesis of alkanes because they react with organic halides to replace the halide group with an R group.
In this particular instance, we intend to synthesize propylcyclohexane. The structure of the lithium diorganocopper (Gilman) reagent required is shown in the image attached to this answer.
Since water is already at 100<span>°C all the energy is used to evaporate it.
Now we can calculate how many </span>mols of water are evaporated with 820kJ.

We calculated that we got 20 mols of water evaporated. Now, all we have to do is find how many grams is a mol of water. Molar mass of water is <span>20.16 g/mol.
</span>The final answer is: