Answer:
HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)
Explanation:
HCOOH is a weak acid and so will not ionised completely in solution.
KOH is a strong base and will ionised completely as shown below
KOH(aq) –> K+(aq) + OH-(aq)
The overall reaction can be written as follow:
HCOOH(aq) + K+(aq) + OH-(aq) —> HCOO-(aq) + K+(aq) + H2O(l)
Cancel out the K+ to obtain the net ionic equation as shown below
HCOOH(aq) + OH-(aq) —> HCOO-(aq) + H2O(l)
The answer should be C. I dont know know if you have misspellings or not
Explanation:
miscible liquids: water and alcohol
immiscible liquids: water and oil
Answer:
The range is also the whole of R
Explanation:
<span>Fluorine
For the group 17 elements (Halogens), the ionization energy decreases as the period increases (the elements become less reactive). And since of the 4 elements given, fluorine is from the lowest period, it has the highest ionization energy.</span>
