25 points and brainiest if correct A, B, C, D
2 answers:
You might be interested in
Answer:
The total hole mobility is 41.67 cm²/V s
Explanation:
Data given by the exercise:
hole mobility due to lattice scattering = ul = 50 cm²/V s
hole mobility due to ionized impurity = ui = 250 cm²/V s
The total mobility is equal:
Answer:
The work transfer per unit mass is approximately 149.89 kJ
The heat transfer for an adiabatic process = 0
Explanation:
The given information are;
P₁ = 1 atm
T₁ = 70°F = 294.2611 F
P₂ = 5 atm
γ = 1.5
Therefore, we have for adiabatic system under compression
Therefore, we have;
The p·dV work is given as follows;
Therefore, we have;
Taking air as a diatomic gas, we have;
The molar mass of air = 28.97 g/mol
Therefore, we have
The work done per unit mass of gas is therefore;
The work transfer per unit mass ≈ 149.89 kJ
The heat transfer for an adiabatic process = 0.