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Answer:
0.23 J
Explanation:
k*(36 - 28) = 23
so k = 23/8 N/cm
W = k(32 - 28)²/2 = 23/8 * 4²/2 = 23 N-cm = 0.23 J
Answer:
V₁ = 6 V
, V₂ = V₃ = 3 V
Explanation:
To solve this circuit we must remember that there are two fundamental types of construction in series and parallel.
* a serial circuit there is only one path for current
in this circuit the constant current in the entire circuit and the voltage is the sum of the voltage of each term
* Parallel circuit in this there are two or more paths for the current
in this circuit the voltage is constant and the east is divided between each branch
with these principles let's analyze the proposed circuit
The DC battery is in parallel with resistor R1 and the equivalent of the other branch,
as in a parallel circuit the voltage is constant
V₁ = 6 V
in the other branch (23) it forms a series construction, where the current is constant
6 = iR₂ + iR₃
as they indicate that each resistance has the same value
6 = 2 iR
V = V₂ = V₃ = 3 V
Answer:
CuCl2 + H2S -> CuS + 2HCl
Explanation:
in the reactants the 2 in 2HCl multiplies to give you 2 Hydrogens and 2 Chlorides.
