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3 years ago

The expression (x − 4)2 is equivalent to x2 − 16 x2 + 16 x2 − 8x + 16 x2 + 8x + 16

Mathematics

1 answer:

zzz [600]3 years ago

4 0

Answer:

Given below

Step-by-step explanation:

The algebraic identity is (a-b)^2

= a^2 + b^2 - 2ab

So it'll be,

(x-4)^2

= x^2 + (4)^2 - (2)(x)(4)

= x^2 -8x + 16

or x^2 +16 -8x

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Help Please!! What is the value of a? Enter your answer in the box. a =

Talja [164]

Answer:

a=15

Step-by-step explanation:

By pythagoras' theorem

25²=20²+a²

625=400+a² group like terms

a²=625-400

a²=225

$\sqrt{a {}^{2} } = \sqrt{225}$

therefore a=15

6 0

3 years ago

How do you solve and simplify

DedPeter [7]

F(x) = 1/(x+2) & g(x) = x/(x-3)

(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:

1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)

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3 years ago

Given b(x) = |x+4], what is b(-10)? -10 -6 8 14

GREYUIT [131]

Answer:

b(-10) = 6

Step-by-step explanation:

Step 1: Define

b(x) = |x + 4|

b(-10) is x = -10

Step 2: Substitute and Evaluate

b(-10) = |-10 + 4|

b(-10) = |-6|

b(-10) = 6

8 0

3 years ago

Read 2 more answers

Select the correct answer.

arlik [135]

Option B is correct

Why

3x=21

3(7) =21

21=21

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

The median of a set of consecutive odd integers is 138. If the greatest integer in the set is 145, what is the least integer in

garri49 [273]

Answer:

131

Step-by-step explanation:

Given that:

Median of a consecutive odd integers = 138

Greatest integer In dataset = 145

Least integer in dataset =

Since the integers are consecutive ;

Number of integers to greatest integer value : Greatest integer - median value = 145 - 138 = 7

Hence, 7 integers before the median value should give us the least integer value ;

138 - 7 = 131

CHECK:

131,132,133,134,135,136,137,138,139,140,141,142,143,144,145

Median = (n+1)/2 th term

Median = (15+1)/2 = 8th term = 138

Highest = 145

Least = 131

7 0

3 years ago