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Natalija [7]
3 years ago
9

If Uranium-240 emits an alpha particle, what does it transmutate into?

Chemistry
1 answer:
aliina [53]3 years ago
7 0

Answer:

i think is b but im not sure

Explanation:

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Which of the following is a reason for cell division?
vekshin1

Answer:

D, to repair the damged cells is noy a reason that cells reproduce by siving in order to maintaon homeostasis.

Explanation:

6 0
3 years ago
Read 2 more answers
Be sure to answer all parts. Write the unbalanced chemical equation to represent each of the following reaction statement. Do no
AnnZ [28]

Answer:

See explanation

Explanation:

An unbalanced chemical equation does not show equal number of atoms of each element on both sides of the reaction equation.

a) KOH + H3PO4 -----> K3PO4 + 3H20

b) Zn + AgCl -------> ZnCl2 + Ag

c) NaHCO3 → Na2CO3 + H2O + CO2

d) NH4NO2 ------> N2 + H2O

e) CO2 + KOH -----> K2CO3 + H2O

5 0
3 years ago
Tertiary alkyl halides show SN1 reactions mostly...... Why?
ankoles [38]

Answer:

Generally SN1 reactions are carried out in polar protic solvents. The energy required for breaking the C-X bond is obtained through solvation of halide ion with the proton of the solvent. Tertiary alkyl halides undergo SN1 reaction very fast because of the high stability of tertiary carbocations.

6 0
3 years ago
The pH of 0.50 M benzoic acid is 2.24. Calculate the change in pH when 2.64 g of C6H5COONa is added to 38 mL of 0.50 M benzoic a
meriva

Answer:

1.93

Explanation:

Moles of C_{6}H_{5}COOH = 38/1000 × 0.50 = 0.019mol

Moles of C_{6}H_{5}COONa = Mass/Molar mass = 2.64/144.10 = 0.018321mol

Final pH = pKa + log([C_{6}H_{5}COONa]/[C_{6}H_{5}COOH]

= -log Ka  + log(mols of C_{6}H_{5}COONa]/mols of C_{6}H_{5}COOH

= -log(6.5 × 10^(-5)) + log (0.018321/0.019)=4.17

change in pH = final - initial pH

= 4.17 - 2.24

=1.93

5 0
4 years ago
a sample of a gas has a volume kf 640 cm^{3} at 100°c and 1490 mmhg,what would be its volume at stp?​
scoundrel [369]

Answer:

V₂ = 918.1 cm³

Explanation:

Given data:

Initial volume = 640 cm³

Initial temperature = 100°C (100+273 = 373 K)

Initial pressure = 1490 mmHg (1490 /760 = 1.96 atm)

Final volume = ?

Final temperature = 273 K

Final pressure = 1 atm

Solution:

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

now we will put the values in formula.

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 1.96 atm × 640 cm³ × 273 K / 373 K × 1 atm

V₂ = 342451.2 atm .cm³ . K / 373 K. atm

V₂ = 918.1 cm³

3 0
3 years ago
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