Answer:
0.295 L
Explanation:
It seems your question lacks the final concentration value. But an internet search tells me this might be the complete question:
" A chemist must dilute 47.2 mL of 150. mM aqueous sodium nitrate solution until the concentration falls to 24.0 mM. He'll do this by adding distilled water to the solution until it reaches a certain final volume. Calculate this final volume, in liters. Be sure your answer has the correct number of significant digits. "
Keep in mind that if your value is different, the answer will be different as well. However the methodology will remain the same.
To solve this problem we can<u> use the formula</u> C₁V₁=C₂V₂
Where the subscript 1 refers to the concentrated solution and the subscript 2 to the diluted one.
- 47.2 mL * 150 mM = 24.0 mM * V₂
And <u>converting into L </u>becomes:
- 295 mL *
= 0.295 L
They’re different in regards to the fact that nebulae are not actively burning while stars are
E since its a physical model i.e. you can touch and feel the model :)
Answer:
Steps of a scientific investigation include:
1. Identifying a research question or problem
2. Forming a hypothesis
3. Gathering evidence
4. Analyzing evidence
5. Deciding whether the evidence supports the hypothesis
6. Drawing conclusions
7. Communicating the results.
<span>7.15 degrees C
The specific heat capacity of water is 4.1813 J/(g*K). So we have 3 values with the units kJ, g and J/(g*K). We can trivially convert from kJ to J by multiplying by 1000. And we want to get a result with the unit K (degrees Kelvin). So let's do it. First, let's cancel out the g unit by multiplying.
4.1813 J/(g*K) * 485 g = 2027.9305 J/K
Now we can cancel out the J unit by dividing. But if we divide by the energy, we'll be left with the reciprocal of K, not K. So instead divide by the J/K unit. So
14500 J / 2027.9305 J/K = 7.150146418 K
Rounding to 3 significant figures gives us 7.15 K.
And since degrees C and degrees K are the same size, the temperature will increase by 7.15 degrees C</span>
