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3 years ago

Which is associated with a fission reaction? *

Chemistry

1 answer:

podryga [215]3 years ago

6 0

Answer: Radioactive waste

Explanation:

The nuclear fission reaction consists of heavy atomic particles or heavy nucleus, like plutonium and uranium and in radioactive heavy metals. In the fission reaction the nucleus get split into equal masses of particles. This process is associated with release of large amount of energy. The fission of radioactive waste can cause deadly mutations in living beings.

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3 years ago

Hydrogen gas (H2) reacts with oxygen gas (O2) and produces water. If one mol of hydrogen reacts with one mole of oxygen, what is

Amiraneli [1.4K]

HI

So, the formula for water is H2O

When you have the same amount of the reactants , hydrogen will be the limiting reactant.
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3 years ago

Acids naturally present in food are safe to eat because they usually are

tangare [24]

A.Weak

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3 years ago

Read 2 more answers

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: E = R_y/n^2 In this equation R_y stands

Katarina [22]

Answer:

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

Explanation:

Given :

The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula:

$E=\frac{R_y}{n^2}$

$R_y=2.18\times 10^{-18} J$ = Rydberg energy

n = principal quantum number of the orbital

Energy of 11th orbit = $E_{11}$

$E_{11}=\frac{2.18\times 10^{-18} J}{11^2}=1.80\times 10^{-20} J$

Energy of 10th orbit = $E_{10}$

$E_{10}=\frac{2.18\times 10^{-18} J}{10^2}=2.18\times 10^{-20} J$

Energy difference between both the levels will corresponds to the energy of the wavelength of the line which can be calculated by using Planck's equation.

$E'=E_{10}-E_{11}=2.18\times 10^{-20} J-1.80\times 10^{-20} J$

$=E'=0.38\times 10^{-20} J$

$\lambda =\frac{hc}{E'}$ (Planck's' equation)

$\lambda = \frac{6.626\times 10^{-34} Js\times 3\times 10^8 m/s}{0.38\times 10^{-20} J}$

$\lambda = 5.2310\times 10^{-5} m\approx 5.23\times 10^{-5} m$

The wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron for the given energy levels is $5.23\times 10^{-5} m$

3 0

3 years ago

Calculate the density of helium if a balloon with a capacity of 5.00 L holds 0.890 g.

liubo4ka [24]

Answer:

Explanation:

Density is m/V. Also, 1 liter = 1000 $cm^3$ . So, we get 0.890/(5*1000) = $1.78*10^{-4}$ g/cm^3. You can convert this to kg/m^3 as well by multiplying it by 10. Depends which one you want.

5 0

3 years ago