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Marizza181 [45]
3 years ago
15

Please help me. It would mean a lot to me please

Chemistry
1 answer:
Nostrana [21]3 years ago
6 0

Answer:

7 cm, 70 mm

Explanation:

there is 7 cm, and to turn that into mm you multiply the cm by 10, giving you 70

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a compound is found to contain 31.1% sulfur and 68.9% chlorine determine the empirical formula for the sulfur and chlorine sampl
ollegr [7]

Answer:

Empirical formula = S₁Cl₂ = SCl₂

Explanation:

The empirical formula of a compound is the simplest whole number ratio of each type of atom in a compound.

This compound contains 31.1% sulfur and 68.9% chlorine.

That is 100g of the compound contains 31.1 g of sulfur and 68.9 g of chlorine.

Convert the mass of each element to moles using the molar mass from the periodic table.

Moles of Sulfur = \frac{31.1}{32.065 } \\

= 0.9699

Moles of Chlorine= \frac{68.9}{35.453 } \\

= 1.9434

Divide each mole value by the smallest number of moles calculated.

Units of sulfur =  \frac{0.9699}{0.9699} \\

= 1

Units of Chlorine =  \frac{1.9434}{0.9699} \\

= 2

Empirical formula = S₁Cl₂ = SCl₂

8 0
3 years ago
How many molecules of CO2 are contained in a 10.0 L tank at 7.53 atm and 485 K?
bonufazy [111]

Answer:PV=nRT

Explanation:find n which are moles and then multiply Avogadro number with moles to get your answer

5 0
3 years ago
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What conversion factor would you use to convert grams to kilograms?
Natalija [7]

Answer:

1kg=1000g

Explanation:

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Calculate the number of nitrogen atoms in 240 g of ammonium nitrate?
gtnhenbr [62]

3.125 i believe is the answer

6 0
3 years ago
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Determine the concentration of a solution prepared by diluting 20.0 mL of 2.00 M NaCl to 250.0 mL. Please show your work.
yawa3891 [41]

0.16 M is the concentration of a solution prepared by diluting 20.0 ml of 2.00 M NaCl to 250.0 ml.

Explanation:

Data given:

Initial volume of NaCl, V1 = 20 ml

initial molarity of the NaCl solution = 2M

Final volume of the NaCl solution = 250 ml

final molarity of the diluted solution = ?

from the information given, the formula for dilution used is:

Minitial Vinitial = Mfinal Vfinal

putting the values in the rearranged equation:

V final = \frac{Minitial Vinitial }{Vfinal}

V final = \frac{20 X 2}{250}

Mfinal = 0.16 M

Thus it can be seen that when a 20 ml solution having molarity of 2M is diluted to 250 ml the molarity decreases to 0.16 M.

6 0
3 years ago
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