Answer:
Empirical formula = S₁Cl₂ = SCl₂
Explanation:
The empirical formula of a compound is the simplest whole number ratio of each type of atom in a compound.
This compound contains 31.1% sulfur and 68.9% chlorine.
That is 100g of the compound contains 31.1 g of sulfur and 68.9 g of chlorine.
Convert the mass of each element to moles using the molar mass from the periodic table.
Moles of Sulfur = 
= 0.9699
Moles of Chlorine= 
= 1.9434
Divide each mole value by the smallest number of moles calculated.
Units of sulfur = 
= 1
Units of Chlorine = 
= 2
Empirical formula = S₁Cl₂ = SCl₂
Answer:PV=nRT
Explanation:find n which are moles and then multiply Avogadro number with moles to get your answer
3.125 i believe is the answer
0.16 M is the concentration of a solution prepared by diluting 20.0 ml of 2.00 M NaCl to 250.0 ml.
Explanation:
Data given:
Initial volume of NaCl, V1 = 20 ml
initial molarity of the NaCl solution = 2M
Final volume of the NaCl solution = 250 ml
final molarity of the diluted solution = ?
from the information given, the formula for dilution used is:
Minitial Vinitial = Mfinal Vfinal
putting the values in the rearranged equation:
V final = 
V final = 
Mfinal = 0.16 M
Thus it can be seen that when a 20 ml solution having molarity of 2M is diluted to 250 ml the molarity decreases to 0.16 M.
