Answer:
Explanation:
The potential energy (PE) we are looking here is gravitational potential energy (GPE).
GPE= mgh,
where m is the mass of an object,
g is the gravitational field strength
h is the height of the object
KE= ½mv²,
where m is the mass and v is the velocity
loss in GPE= gain in KE
mgh= ½mv²
gh= ½v² (<em>divide by m throughout</em>)
Assuming that the object is on earth, then g= 10N/Kg
½v²= 10h (<em>substitute g=10</em>)
v²= 20h (<em>×2 on both sides</em>)
v= √20h (<em>square root both sides</em>)
Answer
given.
Mass of big fish = 15 Kg
speed of big fish = 1.10 m/s
mass of the small fish = 4.50 Kg
speed of the fish after eating small fish =?
a) using conservation of momentum
m₁v₁ + m₂v₂ = (m₁+m₂) V
15 x 1.10 + 4.50 x 0 = (15 + 4.5)V
16.5 = 19.5 V
V = 0.846 m/s
b) Kinetic energy before collision
KE₁ = 9.075 J
Kinetic energy after collision
KE₂ = 6.98 J
Change in KE = 6.98 - 9.075 = -2.096 J
hence,
mechanical energy was dissipated during this meal = -2.096 J
speed of the plane is given as
height of the plane is
acceleration due to gravity is
part a)
when package is dropped its vertical speed is zero so we can use kinematics to find the time of drop
Part b)
Horizontal distance moved by the package is given by
Part c)
final speed in x direction
final speed in y direction
so net speed as it hit the ground will be