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solmaris [256]
2 years ago
11

The decrease of PE for a freely falling object equals its gain in KE, in accord with the conservation of energy. By simple algeb

ra, find an equation for an object's speed v after falling a vertical distance h. Do this by equating KE to its change of PE.
Physics
1 answer:
Delvig [45]2 years ago
4 0

Answer:

v =  \sqrt{20h}

Explanation:

The potential energy (PE) we are looking here is gravitational potential energy (GPE).

GPE= mgh,

where m is the mass of an object,

g is the gravitational field strength

h is the height of the object

KE= ½mv²,

where m is the mass and v is the velocity

loss in GPE= gain in KE

mgh= ½mv²

gh= ½v² (<em>divide by m throughout</em>)

Assuming that the object is on earth, then g= 10N/Kg

½v²= 10h (<em>substitute g=10</em>)

v²= 20h (<em>×2 on both sides</em>)

v= √20h (<em>square root both sides</em>)

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