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levacccp [35]
3 years ago
10

Sediment forms through _______________________ of rocks,

Physics
2 answers:
krok68 [10]3 years ago
8 0
Sediment forms through weathering of rocks
Anna71 [15]3 years ago
7 0

Answer:

C

Explanation:

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When the car comes to a sudden stop, the passenger ________ in motion
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Answer:

If the car comes to a sudden stop, your body tends to keep moving forward.

Explanation:

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1 year ago
A train is traveling at a speed of 50km/hr. How.many hours will it take the train to travel 800 km?
bagirrra123 [75]

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It would take 16 hours

Explanation:

800 divided by 50 = 16

Brainly pls

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3 years ago
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Which of the following does NOT create a mechanical wave? Text to speech
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Light coming through a window!!
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3 years ago
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A ball is thrown horizontally from the top of a building 54 m high. The ball strikes the ground at a point 35 m horizontally awa
Ivanshal [37]

Answer:

V=34.2 m/s

Explanation:

Given that

Height , h= 54 m

Horizontal distance , x = 35 m

Given that , the ball is thrown horizontally , therefore the initial vertical velocity will be zero.

In vertical direction :

We know that

V^2_y=U^2_y+2 g h

Now by putting the values in the above equation we got

V^2_y=U^2_y+2 g h

V^2_y=0^2+2\times 9.81 \times 54

Assume g= 9.81 m/s^2

Thus

V^2_y=1059.48

V_y=\sqrt{1059.48}\ m/s

V_y=32.54 m/s

We also know that

V_y=U_y+ g\times t

32.54=9.81\times t

t=\dfrac{32.54}{9.81}=3.31\ s

In horizontal direction :

x=U_x\times t

U_x=\dfrac{35}{3.31}=10.54\ m/s

Thus the resultant velocity

V=\sqrt{V^2_y+U^2_x}

V=\sqrt{32.54^2+10.54^2}=34.2\ m/s

V=34.2 m/s

Therefore the velocity will be 34.2 m/s.

5 0
4 years ago
Chapter 05, Problem 15 Multiple-Concept Example 7 and Concept Simulation 5.2 review the concepts that play a role in this proble
Llana [10]

Answer:

Explanation:

The question relates to motion on a circular path .

Let the radius of the circular path be R .

The centripetal force for circular motion is provided by frictional force

frictional force is equal to μmg , where μ is coefficient of friction and mg is weight

Equating cenrtipetal force and frictionl force in the case of car A

mv² / R = μmg

R = v² /μg

= 26.8 x 26.8 / .335 x 9.8

= 218.77 m

In case of moton of car B

mv² / R = μmg

v²  = μRg

= .683  x 218.77x 9.8

= 1464.35

v = 38.26 m /s .

3 0
3 years ago
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