Answer
7665 years
Procedure
Let N₀ be the amount of carbon-14 present in a living organism. According to the radioactive decay law, the number of carbon-14 atoms, N, left in a dead tissue sample after a certain time, t, is given by the exponential equation:
N = N₀e^(-λt)
where λ is the decay constant which is related to half-life (T1/2) by the equation:

Here, ln(2) is the natural logarithm of 2.
The percent of carbon-14 remaining after time t is given by N/N₀.
Using the first equation, we can determine λt.
The half-life of carbon-14 is 5,720 years, thus, we can calculate λ using the second equation, and then find t.

Solving the second equation for t, and using the λ we have just calculated we will have
t= 7665 years
Answer:
Lmol⁻¹s⁻¹
Explanation:
The rate law of the given reaction is:-
Rate=k[A][B]
Wherem, k is the rate constant.
Given that:-
Rate = 0.36 mol/Lsec = 0.36 M/sec
[A] = 3.0 M
[B] = 1.0 M
Thus,
Applying in the equation as:-
0.36 M/sec =k × 3.0 M× 1.0 M
k = 0.12 (Ms)⁻¹ = 0.12 Lmol⁻¹s⁻¹
<u>The units of k = Lmol⁻¹s⁻¹</u>
Where is the reaction? The whole question didn't make any sense! Next time please put some time on what you want to ask.
A) If volume increases, temperature increases
The law is V/T, meaning the two values are directly proportional, as one increases, the other increases too.