All categories

3 years ago

A side of a square is 16 units. What is its area?

Mathematics

2 answers:

MatroZZZ [7]3 years ago

7 0

Answer:

256 units²

Step-by-step explanation:

Area of a square is: $A=s^2$

's' - side length

The given square has a side of 16 units.

$A=16^2\\\rightarrow 16*16=256\\\boxed{A=256}$

The area of the square is 256 units².

pogonyaev3 years ago

5 0

Answer:

Step-by-step explanation:

4×4=16

have a great day :)

You might be interested in

A manufacturer produces dice in many different sizes. If the side length of the dice is double, then the volume of the larger di

joja [24]

Answer:

Here you are...

Step-by-step explanation:

If you double one of the dimensions, say change one side from 2 to 4 it doubles the volume. if you were to do this to any side, say double it, it would double the volume. ... It will make the volume 4 times as much also. the volume would go from 30 to 120.

7 0

3 years ago

Calculate the specified probability Suppose that K is a random variable. Given that P(-2.2 ≤ K ≤ 2.2) = 0.725, and that P(K <

belka [17]

Answer:

P(K > 2.2) = 0.1375

Step-by-step explanation:

We have that:

P(-2.2 ≤ K ≤ 2.2) = 0.725

P(K < -2.2) = P(K > 2.2)

It means that the distribution is symmetric.

The sum of all the probabilities is decimal 1.

We have the following probabilities:

P(K < 2.2)

P(-2.2 ≤ K ≤ 2.2)

P(K > 2.2)

P(K < 2.2) + P(-2.2 ≤ K ≤ 2.2) + P(K > 2.2) = 1

Since P(K < 2.2) = P(K > 2.2)

P(K > 2.2) + P(-2.2 ≤ K ≤ 2.2) + P(K > 2.2) = 1

2P(K > 2.2) + 0.725 = 1.

2P(K > 2.2) = 1 - 0.725

2P(K > 2.2) = 0.275

P(K > 2.2) = 0.275/2

P(K > 2.2) = 0.1375

6 0

3 years ago

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution?

elena-s [515]

Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have

$\dfrac{2.5}{x+10}=0.1\implies25=x+10\implies x=15$