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3 years ago

Someone help with this please

Chemistry

1 answer:

Tju [1.3M]3 years ago

3 0

To me I think if the number of snakes increased, the number of rabbits decreases. Hope u got it correct ; )

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How many molecules of carbon dioxide, CO2, are present in 388.1 grams?

swat32

Answer:

53.11× 10²³ molecules

Explanation:

Given data:

Number of molecules of CO₂ = ?

Mass of CO₂ = 388.1 g

Solution:

Formula:

Number of moles = mass/ molar mass

Molar mass of CO₂ = 12× 1 + 16×2

Molar mass of CO₂ = 44 g/mol

Now we will put the values in formula.

Number of moles = 388.1 g/ 44 g/mol

Number of moles = 8.82 moles

Now we will calculate the number of molecules by using Avogadro number.

It is the number of atoms , ions and molecules in one gram atom of element, one gram molecules of compound and one gram ions of a substance.

The number 6.022 × 10²³ is called Avogadro number.

1 mole = 6.022 × 10²³ molecules

8.82 mol × 6.022 × 10²³ molecules / 1 mol

53.11× 10²³ molecules

6 0

3 years ago

True or False ... In a chemical change, a new substance is formed.

nikitadnepr [17]

The answer is true the answer has to be 20 words long so true true true true true true

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3 years ago

Is ninhydren test positive for protein?

lyudmila [28]

The Ninhydrin test is not effective to detect high molecular weight proteins as the steric hindrance limits the ninhydrin from reaching the α-amino groups.

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2 years ago

Help, please X﹏X - The picture in the right is after the water drained out -

lutik1710 [3]

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2 years ago

Read 2 more answers

If we have three different solutions, A, B, and C, each containing 100 g of water, plus respectively 6.84 g of sucrose (C12H22O1

GenaCL600 [577]

Answer:

c. A and C have the same boiling point, but B has a lower one.

Explanation:

The freezing point depression is expressed as:

ΔT = kf×m

Where kf is the freezing point depression constant that depends the nature of the solvent and m is molality (mol of solute/kg of solvent)

Boiling point elevation is:

ΔT = kb×m

Where kb is the ebulloscopic constant of the solvent.

As kf, kb and mass of solvent is the same for A, B and C solutions the only difference will be in moles of solute.

A 6,84g of sucrose are:

6,84g× $\frac{1mol}{342,3g}$ = 0,002 moles

B 0,72g of ethanol are:

0,72g× $\frac{1mol}{46,1g}$ = 0,0016 moles

C 0,40g of sodium hydroxide are:

0,40g× $\frac{1mol}{40g}$ = 0,001 moles

Using Van't Hoff factor that describes the number of moles in solution that comes from 1 mole of solute before dissolving, moles in solution for A, B and C are:

A. moles in solution: 0,02 moles×1 = 0,02 moles in solution

B. moles in solution: 0,016 moles×1 = 0,016 moles in solution

C. moles in solution: 0,01 moles×2 = 0,02 moles in solution

As A has the same moles in solution of C, the freezing point depression will be the same in A and C, and the lower freezing point depression will be in B.

Also, the boiling point will be higher in A and C, and then in B.

Thus:

a. C has the lowest freezing point in the group. FALSE. A and C have the lowest feezing point because have the higher freezing point depression.

b. A, B, and C all have different freezing points. FALSE. As moles of A and C are the same, freezing point will be the same for the solutions.

c. A and C have the same boiling point, but B has a lower one. TRUE.

d. The boiling point of C is lower than that of A or B . FALSE. Boiling point of C and A is higher than B.

e. A, B, and C will all have about the same freezing points. FALSE

7 0

3 years ago