135.1kPa
Explanation:
Given parameters:
T1 = 27°C
P1 = 101.325 kPa
T2 = 127°C
Unknown:
P2 = ?
Solution:
Using a derivative of the combined gas law where we assume that the gas has a constant volume, we can solve for the unknown.
At constant volume:
P1 is the initial pressure
T1 is the initial temperature
P2 is the final pressure
T2 is the final temperature
Take the given temperature to K
T1 = 27 + 273 = 300K
T2 = 127 + 273 = 400K
Input the variables:
P2 = 135.1kPa
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Answer: Final temperature of the gas will be 330 K.
Explanation:
Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
(At constant volume and number of moles)
where,
= initial pressure of gas = 1.00 atm
= final pressure of gas = 1.13 atm
= initial temperature of gas = 
K
= final temperature of gas = ?
Therefore, the final temperature of the gas will be 330 K.
Answer:
It is in the oxidation of NADH to NAD + that lactate dehydrogenase (LDH) plays an important role. LDH catalyzes the following reaction The lactate then diffuses out of the cell and the NAD + is used to continue glycolysis.It is in this manner that the cell continues to produce energy under anerobic conditions.
Explanation:
