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poizon [28]
3 years ago
15

Which map feature best indicates whether two regions have the same elevation?

Physics
2 answers:
Lelechka [254]3 years ago
5 0

Answer:

The answer is contour lines

Bezzdna [24]3 years ago
4 0

Answer:

contour lines

Explanation:

Contour lines is a map feature which help to indicate region of equal height in a map.

In a map, contour lines are usually drawn in irregular circles repeatedly, until the elevations of the region are fully represented.

The inner part of the contour lines usually denote high elevation while the outter contour lines usually denote lower elevation.

Therefore the map feature that best indicates whether two regions have the same elevation is contour lines.

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For brainliest and 100 points
lara31 [8.8K]

Answer:

The answer is below!!

Explanation:

In this problem, Ben is pushing the trolley to north and Gary is pushing it to south. So both the forces are acting 180° opposite to each other. As force is a vector quantity, the net force or total force acting on any object should be calculated by vector addition of number of forces along with their directions. So in this case, if we consider the force Ben is applying as F1 and the force Gary is applying as F2 on the trolley. Then the net or total force acting on the trolley will be . This is because, F1 and F2 are acting opposite to each other in direction.

Hence the answer is A

Hope I helped!!

:)

7 0
2 years ago
Read 2 more answers
Which force requires contact?
NikAS [45]

Answer: C

Explanation:

8 0
4 years ago
Jack (mass 52.0 kg ) is sliding due east with speed 8.00 m/s on the surface of a frozen pond. he collides with jill (mass 49.0 k
dybincka [34]
We must write down laws of conservation of momenta and energy. 
For the law of conservation of momenta will we will use two axes. One will be x-axis that will correspond to the east, and the other one will be y-axis corresponding to the north. Jack will be marked as 1 and Jill will be marked as 2.
Law of conservation of energy:
\frac{m_1v_1^2}{2}=\frac{m_1v'_1^2}{2}+ \frac{m_2v_2^2}{2}\\
m_2v_2^2=m_1v_1^2-m_1v_1'^2\\
v_2=\sqrt{\frac{m_1v_1^2-m_1v_1'^2}{m_2}
This will give us Jill's velocity after the colision.
v_2=6.43\frac{m}{s}
Law of conservation of momenta:
x: m_1v_1=m_1v_1'cos(34)+m_2v_2cos(\theta)\\
y: 0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\
We will use the second equation to get the angle at which the Jill is traveling:
0=m_1v_1'sin(34)-m_2v_2sin(\theta)\\
m_2v_2sin(\theta)=m_1v_1'sin(34)\\
sin(\theta)=\frac{m_1v_1'sin(34)}{m_2v_2}\\
\theta=sin^{-1}(\frac{m_1v_1'sin(34)}{m_2v_2})
When we plug all the number we get:
\theta=27.45^\circ
Please note that this is the angle below the x-axis.

6 0
3 years ago
Does the medium in which a wave travels move along with the wave itself
LUCKY_DIMON [66]
No, the medium does not move, but only vibrates in a perpendicular manner to which the wave is traveling.
4 0
3 years ago
A 100kg couch is being pushed with 196N of force. As it slides along the ground it experiences a coefficient of friction of 0.1.
QveST [7]

Answer:98

Explanation:hope this helps!

4 0
3 years ago
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