The electric field strength of a point charge is inversely proportional to the square of the distance from the charge ... a lot like gravity.
If the magnitude of the field is (2E) at the distance 'd', then at the distance '2d', it'll be (2E)/(2²). That's (2E)/4 = 0.5E .
Answer:
7.50 cm
Explanation:
The formula
1/v + 1/u = 1/f
Is used.
where.
u is the object distance.
v is the image distance.
f is the focal length of the lens.
1/v + 1/15 = 1/5
1/v = 1/5 - 1/15
1/v = (3-1)/15
1/v = 2/15
2v = 15
V = 15/2
V = 7.5 cm
For focal length, f in lens is always taken as negative for concave and positive for convex. ... And for image distance, V in lens it is taken as positive in Convex lens since image is formed on +X side. It is taken as negative in Concave lens since image is formed in -X side of the Cartesian.
Answer:
magnitude of net magnetic field at given point is
Explanation:
As we know that magnetic field due to a long current carrying wire is given as
here we we will find the magnetic field due to wire which is along x axis is given as
r = 2 m
now we have
into the plane
Now similarly magnetic field due to another wire which is perpendicular to xy plane is given as
r = 2 m
now we have
along + x direction
Since the two magnetic field is perpendicular to each other
So here net magnetic field is given as
