Question

Anna applies a force of 19.5 newtons to push a book placed on a table. If the normal force of the book is 51.7 newtons, what is the coefficient of kinetic friction? A0.01 B0.20 C0.38 D0.48

Answer 1

The formula is Force = coefficient of friction times the weight or normal force (in newtons). Plug the numbers in the formula. Do the simple division math. The coefficient of friction should be any number between 0 and 1. If your answer is smaller than 0 or greater than 1, go back and check your work. The answer for this question is C. 0.38   

Answer 2

Answer:

$\mu_k = 0.38$

Explanation:

As we know that the normal force on the book is given as

$F_n = 51.7 N$

also the force required to push the book on the table is given as

$F_f = 19.5 N$

now by the formula of friction force we know that

$F_f = \mu_k F_n$

now plug in all values in it

$19.5 = \mu_k (51.7)$

here we will have

$\mu_k = \frac{19.5}{51.7}$

$\mu_k = 0.38$