Answer:
a) The exit temperature is 39.25°C
b) The highest component surface is 132.22°C
c) The average temperature for air equal to 35°C is a good assumption because the air temperature at the inlet will increase due to the result in the heat gain produced by the duct and whose surface is exposed to a flow of hot.
Explanation:
a) The properties of the air at 35°C:
p = density = 1.145 kg/m³
v = 1.655x10⁻⁵m²/s
k = 0.02625 W/m°C
Pr = 0.7268
cp = 1007 J/kg°C
a) The mass flow rate of air is equal to:
The exit temperature is:
°C
b) The mean fluid velocity is:
The hydraulic diameter is:
The Reynold´s number is:
Assuming fully developed turbulent flow, the Nusselt number is:
The highest component surface temperature is:
°C
Answer: Application.
Explanation:
The question on wether to contine the use of cadavers in the lab for test is being centered around its application. Cadaver which is same as a corpse or dead body is used in crash site during automobil test in lab, some of this cadavers are been disrespected with their applications in the automobile industries because many didn’t consent to be used in those experiments or test.
Answer:
By running multiple regression with dummy variables
Explanation:
A dummy variable is a variable that takes on the value 1 or 0. Dummy variables are also called binary
variables. Multiple regression expresses a dependent, or response, variable as a linear
function of two or more independent variables. The slope is the change in the response variable. Therefore, we have to run a multiple regression analysis when the variables are measured in the same measurement.The number of dummy variables you will need to capture a categorical variable
will be one less than the number of categories. When there is no obvious order to the categories or when there are three or more categories and differences between them are not all assumed to be equal, such variables need to be coded as dummy variables for inclusion into a regression model.
Answer:
repeated?
Explanation:
not really sure what type of answer choices you have
Answer:
True
Explanation:
For point in xz plane the stress tensor is given by![\left[\begin{array}{ccc}Dx_{} &txz\\tzx&Dz\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7DDx_%7B%7D%20%26txz%5C%5Ctzx%26Dz%5C%5C%5Cend%7Barray%7D%5Cright%5D)
where Dx is the direct stress along x ; Dz is direct stress along z ; tzx and txz are the shear stress components
We know that the stress tensor matrix is symmetrical which means that tzx = txz ( obtained by moment equlibrium )
thus we require only 1 independent component of shear stress to define the whole stress tensor at a point in 2D plane
