Question

What is the distance between the points 3, 7 and 15, 6 on a coordinate plane

Answer 1

Answer:

$D=\sqrt{145 }$

Step-by-step explanation:

We are actually using Pythagorean theorem here but to be simple

we can use the equation:

D(distance)=$\sqrt{(x_{1}- x_{2} )^{2} +( y_{1}-y_{2})^{2}}$

=

$D=\sqrt{(15-3)^{2}+(6-7)^{2} } =\\D=\sqrt{(12)^{2}+(-1)^{2} } =\\\\D=\sqrt{144+1 } =\\D=\sqrt{145 }$

(If you meant 16 instead of 6 the answer would be 15)

Hope this helps!