The answer would be that the Electrons get farther from the nucleus. As you go down a group, the Period is increasing, which means that each time a shell is being added on as such the valence electron are moving further away from the nucleus. It is therefore easier for the valence electron to be removed thus why less energy is needed to remove that electron, thus a decrease in ionization energy.
Substance 3 Is most likely to be a Metal for Its malleability and conductive properties.
Answer:
<h3>A Werewolf</h3>
___________
Poem with Compound Words
------------------------------------------
whenever there's a full moon,
I cannot overlook,
some alterations in my ways,
and changes in my look.
my werewolf hair grows everywhere,
my werewolf teeth get long,
my eyesight gets much keener and
I'm muscular and strong.
I get to roam around outside,
the moonlight makes me howl,
these otherworldly sound effects
mean I am on the prawl.
I see the moon is round and full,
I'm moonstruck by the sight,
I've made some telltale changes-so, you'd best stay in tonight.
Explanation:
I HOPE IT HELPS YOUR ENGLISH SUBJECT ;) ★
<span>3.75 gallons need to be drained and replaced with bleach.
Change the problem to "What amounts of a 100% solution and a 4% solution is needed to make 90 gallons of a 8% solution?" Given that, we'll use the following values.
x = amount of 4% solution.
90-x = amount of a 100% solution.
The equation to solve then becomes.
0.04 x + (90-x) = 0.08 * 90
0.04 x + 90 - x = 7.2
Add x to both sides
0.04x + 90 = 7.2 + x
Subtract 0.04x from both sides
90 = 7.2 + 0.96x
Subtract 7.2 from both sides
82.8 = 0.96x
Divide both sides by 0.96
86.25 = x
So you now know that you need 86.25 gallons of the original 4% solution and (90-86.25) = 3.75 gallons of the bleach to make the desired 90 gallons.
So simply drain 3.75 gallons from the tank and replace with bleach.</span>
<u>Answer:</u> The moles of carbon dioxide formed in the reaction is 20 moles.
<u>Explanation:</u>
We are given:
Number of moles of butane = 5.0 moles
The chemical reaction for the combustion of butane follows the equation:
As, oxygen is present in excess. So, it is considered as an excess reagent.
Thus, butane is considered as a limiting reagent because it limits the formation of products.
By stoichiometry of the reaction:
2 moles of butane produces 8 moles of carbon dioxide.
So, 5 moles of butane will produce = of carbon dioxide.
Hence, the moles of carbon dioxide formed in the reaction is 20 moles.