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Otrada [13]
3 years ago
9

A chemist dissolves 1.3 mol NaCl in a 2.0-kg sample of water. What is the boiling point of this solution? (Assume that pure wate

r boils at 100°C and that Kb for water = 0.512°C/m.)
Chemistry
2 answers:
mafiozo [28]3 years ago
8 0
For this problem, the solution is exhibiting some colligative properties since the solute in the solution interferes with some of the properties of the solvent. We use equation for the boiling point elevation for this problem. We do as follows:
<span>
ΔT(boiling point)  = (Kb)mi
</span>ΔT(boiling point)  = (0.512)(1.3/2.0)(2)
ΔT(boiling point)  = 0.67 degrees Celsius
<span>
T(boiling point) = 100 + 0.67 = 100.67 degrees Celsius</span>
lara31 [8.8K]3 years ago
7 0

Answer:

100.67°C

Explanation:

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<br> Determine the frequency of a green laser with a wavelength of 532nm.
const2013 [10]

Answer:

5.64*10^{14}m

Explanation:

C = Fλ

C: Speed of light = 3*10^8m/s

f: Frequency (Hz)

λ: Wavelength (m)

Rearrange formula for wavelength:

C/F = λ

\frac{3*10^8}{532*10^{-9}} =5.64*10^{14}m

6 0
3 years ago
Why might it be useful to determine the elements that a planet or moon is made up of?
GuDViN [60]

to see if its copatible with our environment or to see if there is any unkown element, otherwise i dont know

if wrong very sorry

5 0
3 years ago
After some wood has completely burned in a fire, some of the matter that made up the wood has been destroyed.
nekit [7.7K]
The correct answer is D - When burning a log, the wood combined its components with oxygen. if you could capture the products (CO2, H2O, C, CO, etc), you would have a greater mass than what you started with, burning the log combined the log's components with oxygen in order to burn it.
8 0
3 years ago
Read 2 more answers
A 5g piece of aluminum foil (c=0.897) at 100°C is dropped into a 25g container of water (c=4.184) at 20°C. What is the final tem
jeyben [28]

Answer:

23.6°C

Explanation:

use delta h method

5 0
3 years ago
Convert the composition of the following alloy from atom percent to weight percent (a) 44.9 at% of silver, (b) 46.3 at% of gold,
vesna_86 [32]

Answer:

Mass percentage of gold : 33.35%

Mass percentage of silver: 62.80%

Mass percentage of copper : 3.85%

Explanation:

N=n\times N_A

Where : N = Number of atoms

n = moles

N_A=6.022\times 10^{23} = Avogadro number

Let the total atoms present in the alloy be 100.

Atom percentage of silver = 44.9%

Atoms of of silver = 44.9% of 100 atoms = 44.9

Atomic weight of silver = 107.87 g/mol

Mass of 44.9 silver atoms = 107.87 g/mol ×  44.9 = 4,843.363 g/mol

Atom percentage of gold= 46.3%

Atoms of of gold = 46.3% of 100 atoms = 46.3

Atomic weight of gold = 196.97 g/mol

Mass of 44.9 gold atoms = 196.97 g/mol × 46.3 = 9,119.711 g/mol

Atom percentage of copper = 8.8 %

Atoms of of copper = 8.8% of 100 atoms = 8.8

Atomic weight of copper = 63.55 g/mol

Mass of 44.9 copper atoms = 63.55 g/mol ×  8.8 = 559.24 g/mol

Total mass of an alloy :4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol

Mass percentage of gold :

\frac{4,843.363 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=33.35 \%

Mass percentage of silver:

\frac{9,119.711 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=62.80\%

Mass percentage of copper :

\frac{559.24 g/mol}{4,843.363 g/mol + 9,119.711 g/mol +  559.24 g/mol}\times 100=3.85\%

7 0
3 years ago
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