The solution to your problem is as follows:
<span>2 KClO3 → 2 KCl + 3 O2
</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole
62.6/74.6 = 0.839 moles KCl produced
0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
</span>
Therefore, there are <span>40.27g of O2 produced during the reaction.
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Answer:
See explanation
Explanation:
I have attempted to show the sequence of the reaction between carbamic acid and ammonia to form an amide and water and urea.
The reaction first involves the protonation of ammonia to give ammonium carbamate.
When ammonium carbamate is heated to 130-140 degrees, we obtain urea and water as the final products of the reaction
Answer:

Explanation:
For a charged particle accelerated by an electric field, the kinetic energy gained by the particle is equal to the decrease in electric potential energy of the particle; therefore:

where
is the final kinetic energy
is the initial kinetic energy
q is the charge of the particle
is the potential difference
In this problem,
is the charge of the electron

The electron starts from rest, so its initial kinetic energy is

Therefore,

We can write the final kinetic energy of the electron as

where
is the electron mass
v is the final speed
And solving for v,

Answer:
0 degree C
Explanation:
0 degree C = 32 degree F
0 degree F = -17.7778 degree C