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xxMikexx [17]
3 years ago
11

Calculate the value of Kp at 227°C for the equilibrium: 3 A(g) ⇌ B(g) + D(g) Kc = 5.15

Chemistry
1 answer:
horrorfan [7]3 years ago
3 0
D is the answer I guess
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The jet stream is one of the key winds that moves air masses. In which direction does the jet stream in the United
s344n2d4d5 [400]

Answer: west to east

Explanation:

6 0
3 years ago
When heated, KClO3 decomposes into KCl and O2. KClO3--> 2KCl+ 3O . If this reaction produced 62.6 g of KCl, how much O2 was p
Vladimir [108]
The solution to your problem is as follows:

 <span>2 KClO3 → 2 KCl + 3 O2 

</span><span>MW of KCL = 39.1 + 35.35 = 74.6 g/mole 

62.6/74.6 = 0.839 moles KCl produced 

0.839 moles KCl x 3O2/2KCl x 32g/mole O2 = 40.27g of O2 was produced
</span>
Therefore, there are <span>40.27g of O2 produced during the reaction.
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I hope my answer has come to your help. Thank you for posting your question here in Brainly.


5 0
3 years ago
Here is the reaction of carbamic acid and ammonia to form an amide and water. There is a scheme of a reversible reaction where c
vladimir2022 [97]

Answer:

See explanation

Explanation:

I have attempted to show the sequence of the reaction between carbamic acid and ammonia to form an amide and water and urea.

The reaction first involves the protonation of ammonia to give ammonium carbamate.

When ammonium carbamate is heated to 130-140 degrees, we obtain urea and water as the final products of the reaction

4 0
3 years ago
Consider an electron placed in a region of space in which the electric potential spatially. The electron is placed at a point wh
loris [4]

Answer:

1.33\cdot 10^7 m/s

Explanation:

For a charged particle accelerated by an electric field, the kinetic energy gained by the particle is equal to the decrease in electric potential energy of the particle; therefore:

K_f-K_i = -q\Delta V

where

K_f is the final kinetic energy

K_i is the initial kinetic energy

q is the charge of the particle

\Delta V is the potential difference

In this problem,

q=-1.6\cdot 10^{-19}C is the charge of the electron

\Delta V=-500 V-(-1000 V)=500 V

The electron starts from rest, so its initial kinetic energy is

K_i=0

Therefore,

K_f=-(-1.6\cdot 10^{-19})(500)=8\cdot 10^{-17}J

We can write the final kinetic energy of the electron as

K_f=\frac{1}{2}mv^2

where

m=9.11\cdot 10^{-31} kg is the electron mass

v is the final speed

And solving for v,

v=\sqrt{\frac{2K_f}{m}}=\sqrt{\frac{2(8\cdot 10^{-17})}{9.11\cdot 10^{-31}}}=1.33\cdot 10^7 m/s

5 0
3 years ago
Which temperature is warmer 0° F or 0°C
Y_Kistochka [10]

Answer:

0 degree C

Explanation:

0 degree C = 32 degree F

0 degree F = -17.7778 degree C

4 0
3 years ago
Read 2 more answers
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