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Cerrena [4.2K]
3 years ago
13

What can be known about the salt sample that Gerry is looking at?

Chemistry
1 answer:
Mice21 [21]3 years ago
5 0

Answer:

That its small pointed. Pink(Himalayan salt)or white(normal salt)

Explanation:

Summa dees questions are so stupid, deys makin me salty.

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Emission results in the release of energy without any apparent change in mass or nuclear charge.
Sveta_85 [38]

Answer:

gamma ray

Explanation:

Gamma emission results in the release of energy without any apparent change in mass or nuclear charge.

Properties of Gamma radiations:

Gamma radiations are high energy radiations having no mass.

These radiations are travel at the speed of light.

Gamma radiations can penetrate into the many materials.

These radiations are also used to treat the cancer.

Lead is used for the protection  against gamma radiations because of its high molecular density.

The lead apron are used by the person when treated with gamma radiations.

Lead shields are also used in the wall, windows and doors of the room where gamma radiations are treated, in-order to protect the surroundings.

3 0
4 years ago
Is chromium metal a compound solution suspension or element ?
Levart [38]

Answer: Chromium is both an element and a compound

Explanation:

5 0
4 years ago
Please give me your best chemistry joke. The best joke gets Brainlest.
tia_tia [17]

Answer:

why can you never trust a atom

Explanation:

they make everything up

5 0
3 years ago
Read 2 more answers
How many cm3 are there in 0.25 dm3?
aniked [119]
250cm3 i think im not sure about it though
8 0
3 years ago
Lt takes 4 hr 39 min for a 2.00-mg sample of radium-230 to decay to 0.25 mg. what is the half-life of radium-230?
Rufina [12.5K]
Radioactive decay => C = Co { e ^ (- kt) |

Data:

Co = 2.00 mg
C = 0.25 mg
t = 4 hr 39 min

Time conversion: 4 hr 39 min = 4.65 hr

1) Replace the data in the equation to find k

C = Co { e ^ (-kt) } => C / Co = e ^ (-kt) => -kt = ln { C / Co} => kt = ln {Co / C}

=> k = ln {Co / C} / t =  ln {2.00mg / 0.25mg} / 4.65 hr = 0.44719

2) Use C / Co  = 1/2 to find the hallf-life

C / Co = e ^ (-kt) => -kt = ln (C / Co)

=> -kt = ln (1/2) => kt = ln(2) => t = ln (2) / k

t = ln(2) / 0.44719 = 1.55 hr.

Answer: 1.55 hr
6 0
4 years ago
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