B and i don’t need to explain it says it there hope it helps
Answer:
A. Final Temp = 36.428C and
47.9g ice will melt
Explanation:
Given the following data:
Mass of water (M1) = 45.0g = 0.045kg
Temperature (T1) = 85C = 358k
Mass of ice (M2) = 105g = 0.105kg
Temperature (T2) = 0c = 273k
Specific heat of water (C) = 4.18j/gC = 0.00418kj/kgc
Molar heat of fusion of water = 6.01kj/mol
Therefore, heat required (q) = MCT
M1C(T1-T2) = M2C∆T
By putting the data we have
0.045×0.00418×(358-273) = 0.105×0.00418×∆T
∆t = 0.045×0.00418×85/0.105×0.00418
∆t = 36.428C
Gram of ice that would melt would be 47.9g
Answer:
Blue color of iodine-starch complex is disappear upon hysrolysis
Explanation:
Starch:
Starch is a polysaccharide
it is energy reservoir.
starch is made of monomers of glucose in a chain form.
The simplest form of starch is linear polymer amylose.
Iodine Test:
In this test iodine solution added to the solution to check the presence of starch.
Iodine solution = elemental iodine + KI
Result of Iodine Test:
when the iodine solution (I₃⁻) is added to a solution it show two types of result.
if the starch is present this I₃⁻ form a complex with amylose chain of starch and impart a dark blue color.
if starch is not present then the color will be orange or yellow.
Hydrolysis of Starch:
Hydrolysis of starch is carried out by an enzyme, this enzyme break down the starch into simpler sugar molecule.
So,
When the hydrolysis of starch occur the starch convert to glucose. Then the blue color of starch and iodine complex formed during iodine test is disappear that will be the indication of hydrolysis of starch.
