Answer : To calculate the standard molar enthalpy of complete combustion of liquid ethanol can be done by using the formula given below;
Now, the enthalpies of the elements in their standard state is zero always.
So the
Here we can avoid the heat of enthalpy of oxygen,carbon dioxide and water as they exists in their standard states.
So the
=
Gin is uniform throughout and is a homogenous mixture. If it wasn't you would have awful lumps in your drink :). Hope I helped!
Without doing research before doing an experiment you’d be at risk, example: Chemical reactions that COULD cause chemicals burning through human skin, or setting off an harmful explosion by mixing unknown chemicals together.
Answer:
B. To change from a liquid state to a solid state is called Freezing
Mass of (NH₄)₂U₂O₇ : 410.05 kg
<h3>Further explanation</h3>
Reaction
2UO₂SO₄ + 6NH₃ + 3H₂O → (NH₄)₂U₂O₇ + 2(NH₄)₂SO₄
MW UO₂SO₄ : 366.091
MW (NH₄)₂U₂O₇ : 624.131
MW H₂O : 18.0153
MW NH₃ : 17.0306
mol of 100 kg water :
mol of 100 kg ammonia :
mol of UO₂SO₄ :
Limiting reactants : smallest mol ratio(mol : coefficient)
UO₂SO₄ ⇒ Limiting reactants
mol (NH₄)₂U₂O₇ : mol UO₂SO₄
mass (NH₄)₂U₂O₇
