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3 years ago

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Which mixture is most likely to form a suspension?flour and liquid water, as in gravy metal coins and liquid water sodium chlori

de and liquid water tiny water droplets and the air, as in a cloud?

1 answer:

azamat3 years ago

4 0

<span>The mixture that is most likely to form a suspension is flour and liquid water mixed together, as in a mixture like gravy. A suspension mixture is a mixture that has large solid particles, particles that are large enough for sedimentation.</span>

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For a certain reaction, Kc = 2.76×103 and kf= 6.54×10−4 M−2⋅s−1 . Calculate the value of the reverse rate constant, kr, given th

riadik2000 [5.3K]

Answer:

2.37x10⁻⁷ M⁻².s⁻¹

Explanation:

For a generic reversible reaction:

A + B ⇄ C + D

Kf is the constant of the formation of the products (C and D), Kr is the constant of the formation of the reactants (A and B), and Kc is the general equilibrium constant, which is:

Kc = Kf/Kr

2.76x10³ = 6.54x10⁻⁴/Kr

Kr = 6.54x10⁻⁴/2.76x10³

Kr = 2.37x10⁻⁷ M⁻².s⁻¹

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3 years ago

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Explanation:

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The reaction of NO2 with ozone produces NO3 in a second-order reaction overall.

Brilliant_brown [7]

Answer : The rate of reaction is,

$Rate=4.77\times 10^{-19}M/s$

The appearance of $NO_3$ is, $4.77\times 10^{-19}M/s$

Explanation :

The general rate of reaction is,

$aA+bB\rightarrow cC+dD$

Rate of reaction : It is defined as the change in the concentration of any one of the reactants or products per unit time.

The expression for rate of reaction will be :

$\text{Rate of disappearance of A}=-\frac{1}{a}\frac{d[A]}{dt}$

$\text{Rate of disappearance of B}=-\frac{1}{b}\frac{d[B]}{dt}$

$\text{Rate of formation of C}=+\frac{1}{c}\frac{d[C]}{dt}$

$\text{Rate of formation of D}=+\frac{1}{d}\frac{d[D]}{dt}$

$Rate=-\frac{1}{a}\frac{d[A]}{dt}=-\frac{1}{b}\frac{d[B]}{dt}=+\frac{1}{c}\frac{d[C]}{dt}=+\frac{1}{d}\frac{d[D]}{dt}$

From this we conclude that,

In the rate of reaction, A and B are the reactants and C and D are the products.

a, b, c and d are the stoichiometric coefficient of A, B, C and D respectively.

The negative sign along with the reactant terms is used simply to show that the concentration of the reactant is decreasing and positive sign along with the product terms is used simply to show that the concentration of the product is increasing.

The given rate of reaction is,

$NO_2(g)+O_3(g)\rightarrow NO_3(g)+O_2(g)$

The rate law expression will be:

$Rate=k[NO_2][O_3]$

Given:

Rate constant = $k=1.69\times 10^{-4}M^{-1}s^{-1}$

$[NO_2]$ = $1.77\times 10^{-8}M$

$[O_3]$ = $1.59\times 10^{-7}M$

$Rate=k[NO_2][O_3]$

$Rate=(1.69\times 10^{-4})\times (1.77\times 10^{-8})\times (1.59\times 10^{-7})$

$Rate=4.77\times 10^{-19}M/s$

The expression for rate of appearance of $NO_3$ :

$\text{Rate of reaction}=\text{Rate of appearance of }NO_3=+\frac{d[NO_3]}{dt}$

As, $\text{Rate of reaction}=4.77\times 10^{-19}M/s$

So, $\text{Rate of appearance of }NO_3=+\frac{d[NO_3]}{dt}=4.77\times 10^{-19}M/s$

Thus, the appearance of $NO_3$ is, $4.77\times 10^{-19}M/s$

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3 years ago

What is responsible for the difference in climate between eastern and western California

PilotLPTM [1.2K]

I believe that the answer is D.

I hope this helps. :)

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