Relative formula mass C₅H₁₁ = 71
Now divide the molar mass by the RFM = 142.32 / 71 = 2
Now C₍₅ₓ₂₎H₍₁₁ₓ₂) = C₁₀H₂₂
Hope that helps
If there is a constant loss of 
the concentration of 
will be affected and decrease since 
is a main component of 
.
Hope it helped,
BioTeacher101
B I think lol when something changes the state of matter
Answer:
(40 g O) / (15.99943 g O/mol) x (1 mol CaCO3 / 3 mol O) x (100.0875 g CaCO3/mol) =
83 g CaCO3
So answer D), although three significant digits are not justified.
Your welcome! Please give me brainiest and have a Great day! <3
So that other scientist can repeat their experiments
i hope i got i right
