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2 years ago

Given the balanced equation representing a reaction:

2 answers:

6 0

As aluminium loses 12 moles of electrons oxygen gain 12 moles of electrons.

Explanation
4Al + 3 O2→ Al2O3
first write the ions of Aluminium and oxygen

that is, Aluminium ion is = Al^3+
oxygen ion is = O^2-
therefore one atom of Al loses 3 electrons moles while
one atom of O gain 2 electrons moles

from equation above there a total of number of Al atom are 4 =( 1 x4=4) atoms while
Oxygen atoms are 6= ( 3 x2=6) atoms

therefore the total number of Moles of Al lost is = 3 x 4 = 12 moles of electrons

total number of moles of O gained = 2 x6 = 12 moles of electrons

Mamont248 [21]2 years ago

3 0

Base on the question, which of the following that sates the balance of the reaction and as the aluminum loses 12 moles of electrons, what could be the oxygen, and base on my research, the possible answer among them is in number (2) gains 12 moles of electrons, I hope you are satisfied with my answer and feel free to ask for more

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A box with a mass of 3.5 kg is pushed along a table. If the net force on the box is 35 Newtons, what is the acceleration of the

Vesnalui [34]

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

$a = \frac{f}{m} \\$

m is the mass

f is the force

From the question

mass = 3.5 kg

force = 35 N

We have

$a = \frac{35}{3.5} \\ = 10$

We have the final answer as

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2 years ago

N2-3H2 → 2NH3

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Answer:

6 mols H2 are needed

Explanation:

N2 = 28.01g/mol

H2 = 2.02g/mol

$\frac{2 mol N_{2} }{1}$ * $\frac{3 mol H_{2} }{ 1 mol N_{2} }$ = 6 mol H2

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2 years ago

Part B Change the distance of the electron from the center position as it moves up and down. What relationship do you notice bet

Mrrafil [7]

Answer:

The movement of the electron changes the amplitude of the wave. The farther the electron moves from the center position, the greater the amplitude.

Explanation:

5 0

2 years ago

Read 2 more answers

How many grams of sulfuric acid is needed to neutralize 380 ml of solution with pH = 8.94

erma4kov [3.2K]

Answer : The mass of sulfuric acid needed is $16.23\times 10^{-5}g$ .

Solution : Given,

pH = 8.94

Volume of solution = 380 ml = $380\times 10^{-3}$ $(1ml=10^{-3}L)$

Molar mass of sulfuric acid = 98.079 g/mole

As we know,

$pH+pOH=14\\pOH=14-8.94=5.06$

$pOH=-log[OH^-]$

$5.06=-log[OH^-]$

$[OH^-]=0.00000871=8.71\times 10^{-6}mole/L$

Now we have to calculate the moles of $OH^-$ .

Formula used : $Moles=Concentration\times Volume$

$\text{ Moles of }[OH^-]=\text{ Concentration of }[OH^-]\times Volume\\\text{ Moles of }[OH^-]=(8.71\times 10^{-6}mole/L)\times (380\times 10^{-3}L)=3309.8\times 10^{-9}moles$

For neutralization, equal number of moles of $H^+$ ions will neutralize same number of $OH^-$ ions.

$\text{ Moles of }[OH^-]=\text{ Moles of }[H^+]=3309.8\times 10^{-9}moles$

As, $H_2SO_4\rightarrow 2H^++SO^{2-}_4$

From this reaction, we conclude that

2 moles of $H^+$ ion is given by the 1 mole of $H_2SO_4$

$3309.8\times 10^{-9}$ moles of $H^+$ ion is given by $\frac{3309.8\times 10^{-9}}{2}=1654.9\times 10^{-9}$ moles of $H_2SO_4$

Now we have to calculate the mass of sulfuric acid.

Mass of sulfuric acid = Moles of $H_2SO_4$ × Molar mass of sulfuric acid

Mass of sulfuric acid = $(1654.9\times 10^{-9}moles)\times (98.079g/mole)=162310.94\times 10^{-9}=16.23\times 10^{-5}g$

Therefore, the mass of sulfuric acid needed is $16.23\times 10^{-5}g$ .

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2 years ago

Francium must lose one electron to get a full outer shell. What is the name of the group to which francium belongs

Sedaia [141]

Answer:

Francium (Fr), heaviest chemical element of Group 1 (Ia) in the periodic table, the alkali metal group. It exists only in short-lived radioactive forms.

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2 years ago