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faltersainse [42]
3 years ago
13

I NEED HELP HERE SUM POINTS ( i will report if you put a link and or no answer

Engineering
1 answer:
Y_Kistochka [10]3 years ago
8 0

Answer:

ok I will help you ha Ha ha ha ha ha ha ha ha ha ha ha

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1. A hydro facility operates with an elevation difference of 50 m and a flow rate of 500 m3/s. If the rotational speed is 90 RPM
zloy xaker [14]

Answer:

a) Pelton Turbine

b) P=2.42*10^{5}KW

Explanation:

From the question we are told that:

Height h=50

Flow Rate R= 500 m^3/s

Rotational speed \omega=\90 RPM

Let

Density of water

\rho=1000

Generally the equation for momentum is mathematically given by

P=\rho gRh

P=1000*9.81*500*50

P=2.42*10^{5}KW

8 0
3 years ago
The atmospheric pressure at the top and the bottom of a building is read by a barometer to be 98.5 kPa and 100 kPa, respectively
Fynjy0 [20]

Answer:

127.42m

Explanation:

The air pressure can be understood as the weight exerted by the air column on a body, for this case we must remember that the pressure is calculated by the formula  P=αgh, Where P=pressure, h=gravity, h= height,α=density

So what we must do to solve this problem is to find the length of the air column above and below the building and then subtract them to find the height of the building, taking into account the above the following equation is inferred

h2-h1= building height=H

H=\frac{P1-P2}{g\alpha }

P1=100kPa=100.000Pa

P2=98.5kPa=98.500Pa

α=1.2 kg/m^3

g=9.81m/s^2

H=\frac{100000-98500}{(9.81)(1.2) }=127.42m

4 0
4 years ago
Help please all of the numbers b4 the equal sign are wrong
Nostrana [21]

Answer:

  • 3/5" = 12'
  • 1 3/4" = 35'
  • 1 1/4" = 25'
  • 9/10" = 18'
  • 2 13/20" = 53'

Explanation:

One number is wrong; they all lack units.

The basic ratio is 1" = 20', so you can divide feet by 20 to find inches.

  • 3/5" = 12'
  • 1 3/4" = 35'
  • 1 1/4" = 25'
  • 9/10" = 18'
  • 2 13/20" = 53'

Perhaps you want decimal inches:

  • 0.60" = 12'
  • 1.75" = 35'
  • 1.25" = 25'
  • 0.90" = 18'
  • 2.65" = 53'
7 0
3 years ago
How much work is required to move an electron from the positive terminal to the negative terminal of a 12 V battery? (Knight 21.
Ray Of Light [21]

Answer:

work which is required to move an electron from the positive terminal to the negative terminal is

-4μJ

W = -4μJ

Explanation:

Work required to move the charge

W = qΔV

initial point V₁ = 150V

Final point V₂ = -50V

W = q(V₂ -V₁)

= 20 × 10⁹(-50 - 150)

W = -4μJ

work which is required to move an electron from the positive terminal to the negative terminal is

-4μJ

6 0
3 years ago
Ammonia at 20 C with a quality of 50% and a total mass of 2 kg is in a rigid tank with an outlet valve at the bottom. How much s
Veseljchak [2.6K]

Answer:

16.38L

Explanation:

Through laboratory tests, thermodynamic tables were developed, these allow to know all the thermodynamic properties of a substance (entropy, enthalpy, pressure, specific volume, internal energy etc ..)  

through prior knowledge of two other properties.

Quality is defined as the ratio between the amount of steam and liquid when a fluid is in a state of saturation, this means that since the quality is 50%, 1kg is liquid and 1kg is steam.

then to solve this problem we find the specific volume for ammonia in a saturated liquid state at 20C, and multiply it by mass (1kg)

v(amonia at 20C)=0.001638m^3/kg

m=(0.01638)(1)=0.01638m^3=16.38L

8 0
3 years ago
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