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faltersainse [42]
2 years ago
13

I NEED HELP HERE SUM POINTS ( i will report if you put a link and or no answer

Engineering
1 answer:
Y_Kistochka [10]2 years ago
8 0

Answer:

ok I will help you ha Ha ha ha ha ha ha ha ha ha ha ha

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The collar A, having a mass of 0.75 kg is attached to a spring having a stiffness of k = 200 N/m . When rod BC rotates about the
gladu [14]

Answer:

Speed=1.633 m/s

Force= 20 N

Explanation:

Ideally, v^{2}=\frac {ks^{2}}{m} hence v=s\sqrt {\frac {k}{m}} where v is the speed of collar, m is the mass of collar, k is spring constant and s is the displacement.

In this case, s=100-0=100mm=0.1m since 1 m is equivalent to 1000mm

k is given as 200 N/m and mass is 0.75 Kg

Substituting the given values

v=0.1 m\sqrt \frac {200 N/m}{0.75 Kg}=1.632993162 m/s\approx 1.633 m/s

Therefore, <u>the speed is 1.633 m/s</u>

The sum of vertical forces is given by mg where g is acceleration due to gravity and it's value taken as 9.81 m/s^{2}

Therefore, F_y=0.75\times 9.81=7.3575 N\approx 7.36 N

The sum of forces in normal direction is given by Ma_n=Ks therefore

Ma_n=200*0.1=20 N

Therefore, <u>normal force on the rod is 20 N</u>

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3 years ago
A team of engineers is working on a design to increase the power of a hydraulic lever. They have brainstormed several ideas. Whi
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Answer:

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Explanation:

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2 years ago
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2 years ago
A 200 W vacuum cleaner is powered by an electric motor whose efficiency is 70%. (Note that the electric motor delivers 200 W of
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Answer:

The rate at which this vacuum cleaner supply energy to the room when running is 285.71 Watts.

Explanation:

power efficiency of electric motor = 70% = 0.70

The power output of the vacuum cleaner =P_o= 200 W

The power output of the vacuum cleaner = P_i

Efficiency=\frac{P_o}{P_i}

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P_i=\frac{200 W}{0.70}=285.71 W

The rate at which this vacuum cleaner supply energy to the room when running is 285.71 Watts.

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3 years ago
A hub a signal that refreshes the signal strength.
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