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7nadin3 [17]
2 years ago
13

An experiment based at New Mexico’s Apache Point observatory uses a laser beam to measure the distance to the Moon with millimet

er precision. The laser power is 120 GW, although it’s pulsed on for only 90 ps. The beam emerges from the laser with a diameter of 7.0 mm. It’s then beamed into a telescope aimed at the Moon. When the beam leaves the telescope, it has the telescope’s full 3.5-mm diameter. By the time it reaches the Moon, the beam has expanded to a diameter of 6.5 km.
a. Find the intensity of the beam as it leaves the laser. Express your answer with the appropriate units.
b. Find the intensity of the beam as it leaves the telescope. Express your answer with the appropriate units.
Physics
1 answer:
Anna007 [38]2 years ago
6 0

Answer:

Sorry but i dont know

Explanation:

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Another term for free enterprise system would be capitalism

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How many new facilities does an average facility manager build during his or her career?
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An average facility manager can build one new facility during his or her career.

 

<span>A </span>facilities manager<span> is the ultimate organiser, making sure that a workplace meets the needs of employees by managing all of the required services. In this job, you will be responsible for the </span>management<span> of services and processes that support the core business of an organisation.</span>

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A 2-kg toy car accelerates from 0 to 5 m/s2. It
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10 joules of work is done by the object
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Assume an axon has an internal diameter of 1μm and a myelin sheath 1μm thick. The internal specific resistance is 100 Ω cm. For
SpyIntel [72]

Answer:

1.27\times 10^{12}\Omega/m

Explanation:

We are given that

Diameter=d=\mu m

Thickness=1\mu m

Radius=r=\frac{d}{2}=\frac{1}{2}\mu m=0.5\times 10^{-6} m

Using 1\mu m=10^{-6} m

Dielectric constant=8

Resistance =R=2\times 10^5\Omega cm^2

Internal specific resistance=r=100 ohm cm=100\times \frac{1}{100}\Omega-m=1\Omega m

Using 1 m=100 cm

Internal resistance per unit length=\frac{r}{A}=\frac{1}{\pi r^2}=\frac{1}{3.14\times (0.5\times 10^{-6})^2}=1.27\times 10^{12}\Omega/m

Using \pi=3.14

Internal resistance per unit length=1.27\times 10^{12}\Omega/m

8 0
2 years ago
S To minimize neutron leakage from a reactor, the ratio of the surface area to the volume should be a minimum. For a given volum
erastovalidia [21]

To minimize neutron leakage from a reactor, the ratio of the surface area to the volume should be a minimum. For a given volume V the ratio of the sphere will be \frac{4.83598}{c^{\frac{1}{3} } }.

We know that the surface area and volume of the sphere is given by:

A=4 \pi r^{2}\\V=\frac{4}{3} \pi r^{3}

Therefore, the ratio between the surface area and the volume for the sphere will be:

\frac{A}{V}=\frac{4 \pi r^{2}\\}{\frac{4}{3} \pi r^{3}}=\frac{3}{r}

Equating the volume to the constant c, we will find the value of r.

V=c=\frac{4}{3} \pi r^{3}\\r= (\frac{3c}{4\pi} )^{\frac{1}{3} }

Substituting the value of r in the ration between surface area and volume, we get:

\frac{A}{V}=\frac{3}{ (\frac{3c}{4\pi} )^{\frac{1}{3} }}

Calculating the constants, we get:

\frac{4.83598}{c^{\frac{1}{3} } }

Hence, the ration between surface area and volume is \frac{4.83598}{c^{\frac{1}{3} } }

To learn more about surface area and volume of sphere, refer to:

brainly.com/question/4387241

#SPJ4

3 0
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