Answer:
Check the explanation
Explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
The answer is C hope this helps <span />
Answer:
d. zero
Explanation:
Constant velocity means the acceleration is zero. In this case the velocity does not change,
hope this helps you
have a good day :)
Answer:
5308.34 N/C
Explanation:
Given:
Surface density of each plate (σ) = 47.0 nC/m² = ![47\times 10^{-9}\ C/m^2](https://tex.z-dn.net/?f=47%5Ctimes%2010%5E%7B-9%7D%5C%20C%2Fm%5E2)
Separation between the plates (d) = 2.20 cm
We know, from Gauss law for a thin sheet of plate that, the electric field at a point near the sheet of surface density 'σ' is given as:
![E=\dfrac{\sigma}{2\epsilon_0}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B%5Csigma%7D%7B2%5Cepsilon_0%7D)
Now, as the plates are oppositely charged, so the electric field in the region between the plates will be in same direction and thus their magnitudes gets added up. Therefore,
![E_{between}=E+E=2E=\frac{2\sigma}{2\epsilon_0}=\frac{\sigma}{\epsilon_0}](https://tex.z-dn.net/?f=E_%7Bbetween%7D%3DE%2BE%3D2E%3D%5Cfrac%7B2%5Csigma%7D%7B2%5Cepsilon_0%7D%3D%5Cfrac%7B%5Csigma%7D%7B%5Cepsilon_0%7D)
Now, plug in
for 'σ' and
for
and solve for the electric field. This gives,
![E_{between}=\frac{47\times 10^{-9}\ C/m^2}{8.854\times 10^{-12}\ F/m}\\\\E_{between}= 5308.34\ N/C](https://tex.z-dn.net/?f=E_%7Bbetween%7D%3D%5Cfrac%7B47%5Ctimes%2010%5E%7B-9%7D%5C%20C%2Fm%5E2%7D%7B8.854%5Ctimes%2010%5E%7B-12%7D%5C%20F%2Fm%7D%5C%5C%5C%5CE_%7Bbetween%7D%3D%205308.34%5C%20N%2FC)
Therefore, the electric field between the plates has a magnitude of 5308.34 N/C
Answer:
180°
Explanation:
Friction, if it exists, ALWAYS opposes motion or attempted motion.